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joja [24]
3 years ago
14

Out of the first 15 serves in a volleyball game, 0.6 of them were in bounds. How many of them were not in bounds?

Mathematics
2 answers:
vampirchik [111]3 years ago
8 0
6 serves were not in bounds. 
.6=3/5
3/5=9/15
15-9=6
nikklg [1K]3 years ago
4 0
The answer is 6 because 60 percent went in which is 9.  the other 40 percent is 6
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Math question down below
kramer
X + 4/5 = 11
x = 11 - 4/5
x = 55/5 - 4/5
x = 51/5 or 10 1/5

or u can do it this way..
x + 4/5 = 11.....multiply everything by common denominator of 5
5x + 4 = 55
5x = 55 - 4
5x = 51
x = 51/5 or 10 1/5
7 0
3 years ago
If
arlik [135]

Given:

In a right angle triangle θ is an acute angle and \tan\theta =\dfrac{3}{5}.

To find:

The value of \cos \theta.

Solution:

In a right angle triangle,

\tan \theta=\dfrac{Perpendicular}{Base}

We have,

\tan\theta =\dfrac{3}{5}

It means the ratio of perpendicular to base is 3:5. Let 3x be the perpendicular and 5x be the base.

By using Pythagoras theorem,

Hypotenuse=\sqrt{Perpendicular^2+base^2}

Hypotenuse=\sqrt{(3x)^2+(5x)^2}

Hypotenuse=\sqrt{9x^2+25x^2}

Hypotenuse=\sqrt{34x^2}

Hypotenuse=x\sqrt{34}

In a right angle triangle,

\cos \theta=\dfrac{Base}{Hypotenuse}

\cos \theta=\dfrac{5x}{x\sqrt{34}}

\cos \theta=\dfrac{5}{\sqrt{34}}

Therefore, the value of \cos \theta is \dfrac{5}{\sqrt{34}}.

8 0
2 years ago
Mona's math certificate is 10 inches tall and 14 inches wide. Mona wants to put the certificate in a fancy frame that costs $1.0
swat32

Answer:

$48.96

Step-by-step explanation:

Given data

Length= 10inches

Width=14 inches

Let us find the perimeter of the  certificate

P=2L+2W

P= 2*10+2*14

P=20+28

P= 48 inches

Hence if 1 inche cost $1.02

Then 48 inches will cost x

cross multiply we

x= 48*1.02

x= $48.96

Hence it will cost $48.96 to frame the certificate

6 0
3 years ago
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Step-by-step explanation:

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