There are many...since 1 yard is 3 feet, then 12 yards, which is 12 times as much , is 12 x 3 or 36 feet.....
Answer:
a) 4 - 
b) 1 - 
c) 6 - 
Step-by-step explanation:
It simply asks the steps to go from the original displacement formula to isolate a (the acceleration). It's just a matter of moving items around.
We start with:

We then move the vt part on the left side, then multiply each side by -1 (to get rid of the negative on the at side and to match answer choice #4):

Then we multiply each side by 2 to get rid of the 1/2, answer #1:

Finally, we divide each side by t^2 to isolate a (answer #6):

Answer:
a ^ 2 - b ^ 2 = ( a + b ) ( a - b ) where a = 4p and b = 3q.
( 4p + 3q ) ( 4p - 3q )
Answer:
True or False
2. When graphing inequalities, a dashed line is used for < or > signs.
True or False
3. If you were to graph x > 6, the circle would be closed and to the left.
True or False
4. On a number line, if you were to graph an equation with a less than sign or a great than sign, < or > respectively, you would use an open circle
True or False