Uh can you show the problems? Because I wouldn’t be able to answer your question if you don’t show me the expressions
The polynomial

may have solutions which are the divisors of -20, therefore -20 has the following divisors:

.
If x=1, then

,
if x=-1, then

,
if x=2, then

, then x=2 is a solution and you have the first factor (x-2).
If x=-2, then

, then x=-2 is a solution, so you have the second factor (x+2).
Since x-2 and x+2 are two factors of

, then the polynomial

is a divisor of

and dividing the polynomial

by

you obtain

.
Answer:
927.3 feet per hour
Step-by-step explanation:
first determine how many seconds are in one hour
there are 60 seconds in one minute and 60 minutes in one hour
so there are 60x60, or 3600 seconds in one hour
now you can create a proportion of inches/seconds = inches/seconds
let 'x' = inches per hour
34/11 = x/3600
cross-multiply to get:
11x = 3600x34
11x = 122,400
x = 122,400/11
x = 11,127.3 inches per hour
to determine how many feet per hour you must divide 11,127.3 inches by 12
this equals 927.3 feet per hour
For this case what you should do is use the following trigonometric relationship:
tan (x) = C.O / C.A
Where
x: angle
C.O: opposite leg
C.A: adjoining catheto
Substituting the values we have:
tan (60) = long / short
tan (60) = long / 2
long = 2 * tan (60)
long = 3.46
Answer:
long = 3.46