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BlackZzzverrR [31]
3 years ago
6

Please explain, 2 (4m-5) - (6m-11) =33

Mathematics
1 answer:
zlopas [31]3 years ago
7 0

Answer:

m = 16

Step-by-step explanation:

2(4m - 5) - (6m - 11) = 33 (Given)

8m - 10 - 6m + 11 = 33 (Distribute)

2m + 1 = 33 (Combine like terms)

2m = 32 (Subtract 1 on both sides)

m = 16 (Divide 2 on both sides)

You can check by substituting your answer into the equation:

2(4(16) - 5) - (6(16) - 11) = 33

2(64 - 5) - (96 - 11) = 33

2(59) - (85) = 33

118 - 85 = 33

33 = 33

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Find the smallest positive $n$ such that \begin{align*} n &amp;\equiv 3 \pmod{4}, \\ n &amp;\equiv 2 \pmod{5}, \\ n &amp;\equiv
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4, 5, and 7 are mutually coprime, so you can use the Chinese remainder theorem right away.

We construct a number x such that taking it mod 4, 5, and 7 leaves the desired remainders:

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so we multiply the last term by 7.

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3 years ago
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3 years ago
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