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Answer:
Given
Per Kg of body mass, there is 3 gram of potassium
And abundance of three isotopes are as follows
Potassium-39, Potassium-40, and Potassium-41. Have abundances respectively as 93.26%, 0.012% and 6.728%.
1) A body weighing 80 Kg will have 240 grams of potassium. And the amount of Potassium-40 will be 0.012% of 240 gram
= 240*0.012/100 = 0.0288 gram.
2) Dose in (Gy) = (energy absorbed)/(mass of the body) = ( 1.1*106*1.6*10-19)/(80) = 22*10-10 J/kg
Dose (in siverts) = RBE*Dose(in Gy) = 1.2*22*10-10 = 26.4*10-10
I love statistics So I will use The principles of it
![\begin{cases}\\ \dag \: \underline{\Large\bf Formulas\:of\:Statistics} \\ \\ \bigstar \: \underline{\rm Mean:} \\ \\ \bullet\sf M=\dfrac {\Sigma x}{n} \\ \bullet\sf M=a+\dfrac {\Sigma fy}{\Sigma f} \\ \\ \bullet\sf M=A +\dfrac {\Sigma fy^i}{\Sigma f}\times c \\ \\ \bigstar \: \underline{\rm Median :} \\ \\ \bullet\sf M_d=\dfrac {n+1}{2} \:\left[\because n\:is\:odd\:number\right] \\ \bullet\sf M_d=\dfrac {1}{2}\left (\dfrac {n}{2}+\dfrac {n}{2}+1\right)\:\left[\because n\:is\:even\:number\right] \\ \\ \bullet\sf M_d=l+\dfrac {m-c}{f}\times i \\ \\ \bigstar \: {\boxed{\sf M_0=3M_d-2M}}\end {cases}](https://tex.z-dn.net/?f=%20%5Cbegin%7Bcases%7D%5C%5C%20%20%5Cdag%20%5C%3A%20%5Cunderline%7B%5CLarge%5Cbf%20Formulas%5C%3Aof%5C%3AStatistics%7D%20%5C%5C%20%5C%5C%20%5Cbigstar%20%5C%3A%20%5Cunderline%7B%5Crm%20Mean%3A%7D%20%5C%5C%20%5C%5C%20%5Cbullet%5Csf%20M%3D%5Cdfrac%20%7B%5CSigma%20x%7D%7Bn%7D%20%5C%5C%20%5Cbullet%5Csf%20M%3Da%2B%5Cdfrac%20%7B%5CSigma%20fy%7D%7B%5CSigma%20f%7D%20%5C%5C%20%5C%5C%20%5Cbullet%5Csf%20M%3DA%20%2B%5Cdfrac%20%7B%5CSigma%20fy%5Ei%7D%7B%5CSigma%20f%7D%5Ctimes%20c%20%5C%5C%20%5C%5C%20%5Cbigstar%20%5C%3A%20%5Cunderline%7B%5Crm%20Median%20%3A%7D%20%5C%5C%20%5C%5C%20%5Cbullet%5Csf%20M_d%3D%5Cdfrac%20%7Bn%2B1%7D%7B2%7D%20%5C%3A%5Cleft%5B%5Cbecause%20n%5C%3Ais%5C%3Aodd%5C%3Anumber%5Cright%5D%20%5C%5C%20%5Cbullet%5Csf%20M_d%3D%5Cdfrac%20%7B1%7D%7B2%7D%5Cleft%20%28%5Cdfrac%20%7Bn%7D%7B2%7D%2B%5Cdfrac%20%7Bn%7D%7B2%7D%2B1%5Cright%29%5C%3A%5Cleft%5B%5Cbecause%20n%5C%3Ais%5C%3Aeven%5C%3Anumber%5Cright%5D%20%5C%5C%20%5C%5C%20%5Cbullet%5Csf%20M_d%3Dl%2B%5Cdfrac%20%7Bm-c%7D%7Bf%7D%5Ctimes%20i%20%5C%5C%20%5C%5C%20%5Cbigstar%20%5C%3A%20%7B%5Cboxed%7B%5Csf%20M_0%3D3M_d-2M%7D%7D%5Cend%20%7Bcases%7D)
Answer:
Males need only one copy of the color-blind allele to show the trait.
Explanation:
color blindness is inherited by sex and needs two dominant allele for females like xBxB and for males need one dominant allele xB y which means the male need one copy of this allele to be color blinded
