Answer:
0.0879 is the probability that out of 5 randomly selected consumers, three are comfortable with delivery by drones.
Step-by-step explanation:
We are given the following information:
We treat drone deliveries as a success.
P(consumers comfortable having drones deliver) = 25% = 0.25
Then the number of consumers follows a binomial distribution, where
where n is the total number of observations, x is the number of success, p is the probability of success.
We have to evaluate:
P(Exactly 3 customers out of 5 are comfortable with delivery by drones)
Here,
![n = 5\\x = 3\\p = 0.25\\q = 1 - p = 1-0.25=0.75](https://tex.z-dn.net/?f=n%20%3D%205%5C%5Cx%20%3D%203%5C%5Cp%20%3D%200.25%5C%5Cq%20%3D%201%20-%20p%20%3D%201-0.25%3D0.75)
Putting values, we get,
0.0879 is the probability that out of 5 randomly selected consumers, three are comfortable with delivery by drones.