The limit does not exist. There are infinitely many infinite discontinuities at
, where
. The function oscillates wildly between negative and positive infinity.
Answer:
Emilia bought 28 sweets
Step-by-step explanation:
now they have 65, but before they had 65-15+10 because earlier, zakiah had ten more sweets than now and Emilia had 15 less, so basically, if you wanna calculate number of sweets they had earlier, you have to make minus from plus and in reverse too.
65-15+10=60 and now just do that simply ratio
E:Z=7:8
E+Z=7x+8x
60=15x
4=x
7x=28=Emilia
8x=32=Zakiah
Accuracy test:
(28+15)+(32-10)=65
28 is 4•7 and 32 is 4•8
The correct answer is B: y ≥ 1/3x - 1
(0,0) ⇒ within the shaded area
0 ≥ 1/3(0) - 1
0 ≥ 0 - 1
0 ≥ -1
True
(0, -3) ⇒ not within the shaded area
-3 ≥ 1/3(0) -1
-3 ≥ 0 - 1
-3 ≥ -1
False
Solve:
<span>-X - Y - Z =-8
- 4X +4Y +5Z=7
2X + 2Z =4 is the same as x + z = 2. Thus, z = 2 - x.
Subst. 2 - x for z in the 1st and second equations.
</span>-X - Y - Z =-8 becomes -x - y - (2 -x) = -8
- 4X +4Y +5Z=7 becomes -4x + 4y + 5(2-x) = 7
Now we have 2 equations in only 2 unknowns. Let's simplify them!
-x - y - 2 + x = -8 which becomes -y = -6, or y = 6
-4x + 4y + 10 - 5x = 7 which becomes -9x + 4y = 7 - 10 = -3
Now substitute 6 for y in this last equation: -9x + 4(6) = -3, or
-9x + 24 = -3, or
-9x = - 27 => x = 3
Then x = 3, y = 6 and z = 2 - x, or z = 2-3, or z = -1.
The solution is (3, 6, -1). Check it!!