Question

A potential customer for an $85,000 fire insurance policy possesses a home in an area that, according to experience, may sustain a total loss in a given year with probability of .001 and a 50% loss with probability .01. Ignoring all other partial losses, what premium should the insurance company charge for a yearly policy in order to break even on all $85,000 policies in this area?

Answer 1

Answer:

$510

Step-by-step explanation:

Let X be the amount of money that insurance company will have to pay on the policy for home.

It is given that according to experience, may sustain a total loss in a given year with probability of .001 and a 50% loss with probability .01. Ignoring all other partial losses.

It means the possible values for variable X are 0, 42500 and 85000.

$P(X=42500)=0.01$

$P(X=85000)=0.001$

We have only three possible values of X. So,

$P(X=0)+P(X=42500)+P(X=85000)=1$

$P(X=0)=1-0.01-0.001=0.989$

The expected amount of money is

$E(X)=\sum xP(x)$

$E(X)=0\cdot P(X=0)+42500\cdot P(X=42500)+85000\cdot P(X=85000)$

$E(X)=0\cdot (0.989)+42500\cdot (0.01)+85000\cdot (0.001)$

$E(X)=0+425+85$

$E(X)=510$

Therefore, the insurance company should charge a premium of $510 for a yearly policy in order to break even on all $85,000 policies in this area.