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REY [17]
3 years ago
9

3x + 5y = 78

Mathematics
2 answers:
fenix001 [56]3 years ago
8 0

Answer:  The correct option is (B) 6.

Step-by-step explanation:  We are given to select the x co-ordinate of the point of intersection of the following lines.

3x+5y=78~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\2x-y=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)

To find the x co-ordinate of the point of intersection, we need to solve the given system of equation to find the point of intersection.

From equation (ii), we have

2x=y\\\\\Rightarrow y=2x~~~~~~~~~~~~~~~~~~~~~~~~(iii)

Substituting the value of y from equation (iii) in equation (i), we get

3x+5(2x)=78\\\\\Rightarrow 3x+10x=78\\\\\Rightarrow 13x=78\\\\\Rightarrow x=\dfrac{78}{13}\\\\\Rightarrow x=6.

Thus, the x co-ordinate of the point of intersection of the given lines is 6.

Option (B) is CORRECT.

zysi [14]3 years ago
5 0
Hello here is a solution :
<span>3x + 5y = 78 .... (1)
2x - y = 0 ... (2)
from (2) : y = 2x
in (1) : 3x+5(2x) =78
            13x = 78
x= 6
 but : y =2x    y=2(6) = 12
answer : x=6</span>
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Answer:

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Step-by-step explanation:

We have the following equation:

x^2 -18 x +8 =0

We can use the quadratic formula given by:

x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}

Where:

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And replacing we got:

x = \frac{-(-18) -\sqrt{(-18)^2 -4*1*8}}{2} = \frac{18 -2 \sqrt{73}}{2}= 9 -\sqrt{73}

x = \frac{-(-18) +\sqrt{(-18)^2 -4*1*8}}{2} = \frac{18 +2 \sqrt{73}}{2}= 9 +\sqrt{73}

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