The correct answer for this problem is C.) reflection across y=x .
Answer:
Step-by-step explanation:
for x, then 7 = (x1+9) /2
14 = x1+9
5 = x1
for y , then 4 = (y1+7 ) /2
8 = y1 + 7
1 = y1
J = (5,1)
Answer:
![\boxed{\text{[2, 33]}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Ctext%7B%5B2%2C%2033%5D%7D%7D)
Step-by-step explanation:
The range is the spread of the y-values (minimum to maximum distance travelled).
The minimum is 2 mi, and the maximum is 33 mi, so the range is from 2 to 33.
In interval notation, the range is ![\boxed{\textbf{[2, 33]}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Ctextbf%7B%5B2%2C%2033%5D%7D%7D)
The answer is the last one D that is the correct answer
good lock!!!
Answer:
jamal traveled 5 hours at 55mph and 4 hours at 60mph
Step-by-step explanation:
time x will be time jamal travels 55 mph (in hours)
time y will be time jamal travels 60 mph (in hours)
distanced traveled 520 miles
distance = time*speed
520= x*55+y*60
520=55x+60y
jamal traveled for 9 hours
9 hours is composed to the two times x and y
9=x+y
then
x=9-y
substitute into 520=55x+60y
520=55(9-y)+60y
520=495-55y+60y
520=495+5y
25=5y
y=5
x+y=9
x+5=9
x=4
time x is time jamal travels 55 mph (in hours)
time y is time jamal travels 60 mph (in hours)
jamal traveled 5 hours at 55mph and 4 hours at 60mph
