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3 years ago

Can someone solve this?

Mathematics

1 answer:

Elis [28]3 years ago

3 0

Answer:

7. 206.9955 in^2

8.482.1372 ft^2

9.256 ft^2

Step-by-step explanation:

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How would i solve this the shaded region is the whole inside circle.

rosijanka [135]

Answer:

34.48cm²

Step-by-step explanation:

Assuming the shaded area doesn't contain the triangle:

area of triangle = bh/2

area of triangle = 4(2)/2

area = 4

area of circle = πr²

area = π3.5²

area = 38.48

area of shaded = 38.48 - 4

area = 34.48cm²

6 0

1 year ago

What is the difference between the rational expressions below? 3x+1/x^2-5/x

Tom [10]

Answer:

(3x^2-5x-5)/(x^2+x) <--- answer

Step-by-step explanation:

3x/(x+1) - 5/x = (3x^2 - 5(x+1) )/[ x(x+1) ]

= (3x^2 - 5x - 5)/(x^2 + x)

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3 years ago

Scale drawing of the electronics board

lora16 [44]

Area of the electronic board is 9000 cm2

Step-by-step explanation:

Write ratios to represent the unknown actual length and width of the display to the scale length and width of the display.

The Electronic board always seems like a rectangular shape

Length= scale÷Actual = 5/36 = 5×36 = 180cm

$Length= scale÷Actual = 5/36 = 5×36 = 180cm$

Width=scale÷Actual = 1/50 = 1×50 = 50cm

$Width=scale÷Actual = 1/50 = 1×50 = 50cm$

Area of Rectangle = legnth × width

= 180cm × 50cm = 9000 cm2

$= 180cm × 50cm = 9000 cm2$

Area of the electronic board is 9000 cm2

6 0

3 years ago

Write an equation of a line that passes through the point (2,0) and is perpendicular to the line y = − 1/2 x + 3.

tatyana61 [14]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

Find all roots: x^3 + 7x^2 + 12x = 0 Show all work and check your answer.

Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

Solution:

We have been given a cubic polynomial.

$x^{3}+7 x^{2}+12 x=0$

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

$x^{3}+7 x^{2}+12 x=0$

$x\left(x^{2}+7 x+12\right)=0$ ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

$x^{2}+7 x+12=0$

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

$\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}$

Therefore, the two roots are:

$\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}$

And,

$\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}$

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0

3 years ago