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2 years ago

NEEDED NOW

Mathematics

2 answers:

stealth61 [152]2 years ago

8 0

Answer:

D. The velocity of the bike when Jack stopped pedaling.

Step-by-step explanation:

I took a test with this question and got it right .

zmey [24]2 years ago

5 0

Answer:

Step-by-step explanation:

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Find a parametrization r ( t ) r(t) of the line through the origin whose projection on the x y - xy- plane is a line of slope 8

ankoles [38]

Answer:

please check the attached file for the answer

Step-by-step explanation:

the explanation is in the attached file

8 0

3 years ago

The tax rate is 3.9% What is the tax on 42$? Round to the nearest hundredth

mafiozo [28]

To find the total price, we use this equation:
42 + 0.039(42)
We can make it simpler:
1.039(42)
Multiply:
43.638
Because we're rounding
The total price is $43.64

7 0

3 years ago

Is 7/8 or 11/10 closer to 1? How did you decide anybody help please?

erik [133]

Let

A-----> $\frac{7}{8}$

B-----> $\frac{11}{10}$

C-----> $1$

we know that

Point A-------> Multiply numerator and denominator by $10$

$\frac{7*10}{8*10} =\frac{70}{80}$

Point B-------> Multiply numerator and denominator by $8$

$\frac{11*8}{10*8} =\frac{88}{80}$

Point C-------> Multiply numerator and denominator by $80$

$\frac{1*80}{1*80} =\frac{80}{80}$

Find the distance Point A to Point C

$\frac{80}{80} -\frac{70}{80} =\frac{10}{80}$

Find the distance Point B to Point C

$\frac{88}{80} -\frac{80}{80} =\frac{8}{80}$

therefore

$\frac{8}{80} < \frac{10}{80}$

Point B is closer to Point C

$\frac{11}{10}$ is closer to $1$

the answer is

$\frac{11}{10}$ is closer to $1$

5 0

3 years ago

Read 2 more answers

I need help I can’t figure it out

dusya [7]

Answer:

$\large\boxed{\dfrac{41p}{70q^4(r-9)^2}}$

Step-by-step explanation:

$\dfrac{2p^4}{5q^5(r-9)^3}\cdot\dfrac{41q(r-9)}{28p^3}\\\\=\dfrac{2\!\!\!\!\diagup^1\cdot41}{5\cdot28\!\!\!\!\!\diagup_{14}}\cdot\dfrac{q\!\!\!\!\diagup}{q^{5\!\!\!\!\diagup^4}}\cdot\dfrac{(r\!\!\!\!\!\!{--}-9)\!\!\!\!\!\!{--}}{(r-9)^{3\!\!\!\!\diagup^2}}\cdot\dfrac{p^{4\!\!\!\!\diagup}}{p^3\!\!\!\!\!\!\diagup}\\\\=\dfrac{41}{70}\cdot\dfrac{1}{q^4}\cdot\dfrac{1}{(r-9)^2}\cdot\dfrac{p}{1}\\\\=\dfrac{41p}{70q^4(r-9)^2}$

7 0

2 years ago

Simplify rational equations y=x^2+3x/x Show work, please

lora16 [44]

Answer:

Step-by-step explanation:

2y x 3x

7 0

3 years ago