Answer:
f. sqrt 7 meters
Step-by-step explanation:
we use Pythagoras' theorem here,
let the unknown side be x,
therefore,
=> 3² + x² = 4²
=> x² = 16 - 9
=> x = √7 m
Answer:
Correct option: (a) 0.1452
Step-by-step explanation:
The new test designed for detecting TB is being analysed.
Denote the events as follows:
<em>D</em> = a person has the disease
<em>X</em> = the test is positive.
The information provided is:

Compute the probability that a person does not have the disease as follows:

The probability of a person not having the disease is 0.12.
Compute the probability that a randomly selected person is tested negative but does have the disease as follows:
![P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264](https://tex.z-dn.net/?f=P%28X%5E%7Bc%7D%5Ccap%20D%29%3DP%28X%5E%7Bc%7D%7CD%29P%28D%29%5C%5C%3D%5B1-P%28X%7CD%29%5D%5Ctimes%20P%28D%29%5C%5C%3D%5B1-0.97%5D%5Ctimes%200.88%5C%5C%3D0.03%5Ctimes%200.88%5C%5C%3D0.0264)
Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:
![P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188](https://tex.z-dn.net/?f=P%28X%5E%7Bc%7D%5Ccap%20D%5E%7Bc%7D%29%3DP%28X%5E%7Bc%7D%7CD%5E%7Bc%7D%29P%28D%5E%7Bc%7D%29%5C%5C%3D%5B1-P%28X%7CD%29%5D%5Ctimes%7B1-%20P%28D%29%5D%5C%5C%3D0.99%5Ctimes%200.12%5C%5C%3D0.1188)
Compute the probability that a randomly selected person is tested negative as follows:


Thus, the probability of the test indicating that the person does not have the disease is 0.1452.
Answer:
200 cm^2
Step-by-step explanation:
Add up all areas
4 x 6 x 1/2 = 12
4 x 6 x 1/2 = 12
3 x 11 = 33
3 x 11 = 33
6 x 11 = 66
12 + 12 + 33 + 33 + 66 = 200
The variable can be g for games being bowled and the expression is 25g
Answer:
Step-by-step explanation:
Step 1:
x - > number of Avocado
y -> number of melon
Step 2:
x ≤ 3y
x + y ≥ 20
Step 3:
x + y≥ 20
y ≥ -x + 20
Step 4:
( 1 , 20)
x ≤ 3y ; y≥ -x + 20
1 ≤ 3*20 ; 20 ≥ -1 + 20
1 ≤ 60 ; 20 ≥ 19