HELP!!

1 answer:

5 0

f(x)=x^2+2x−24
x intercept is where y=0 let f(x)=y
x^2+2x−24=0
(x+6)(x-4) ,x=-6, x=4

2)

f(x)=x^2+17x+72
x^2+17x+72 =0

(x+8)(x+9) x= - 8,- 9

3)
f(x)=x^2+6x+11
x=-3 minimum

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