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amid [387]
3 years ago
6

I need some help with this problems.I will apreciate the answers:)))))

Mathematics
1 answer:
pentagon [3]3 years ago
4 0
Q64 Initial: 1/4 can covers 3/4 of a wall
A full can is 4/4 so four times the amount is used when a full can is used as 4*(1/4) is 4/4.
This means he can cover 4 times the amount initially covered.
If you get stuck with this final step then I can explain in the comments just ask :)
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PLEASE HELPP!! How do I solve 4(x-8) = -2(x-5). Picture above.
dimulka [17.4K]

Answer:

x=7

Step-by-step explanation:

4(x-8)= -2(x-5)

4x+32= -2x+10

+2x          +2x

6x-32=10

    +32    +32

6x= 42

divide by 6 on both sides

x=7

6 0
2 years ago
The side of a square is 2 7/2 inches. Using the area formula A = s2, determine the area of the square.
o-na [289]
<span>the answer A=49 square inches</span>
3 0
2 years ago
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Please jdkhskslsjje
castortr0y [4]

Answer:

3/8

Step-by-step explanation:

1- 1/4 +(1/2 x 3/4)

1. subtract 1/4 to get 3/4 (how much time she has left in class).

2. multiply 3/4 by 1/2 to find how much half of 3/4 is.

3. Half of 3/4 is 3/8 so that's how much time she spent on the balance beam.

3 0
3 years ago
Round 3.14961 to the nearest tenth
Alinara [238K]
The answer is 3.1 because 4 is under 5
3 0
2 years ago
Read 2 more answers
A Warming Liquid - A liquid is taken out of a refrigerator and placed in a warmer room, where its temperature, in F, increases o
IRISSAK [1]

Answer:

The temperature at the start is 35F

The temperature of the room is 74F

<em></em>

Step-by-step explanation:

Given

T(m) = 74 - 39(0.87)^m

Solving (a): The temperature at the start.

To do this, we set: m = 0

So, we have:

T(0) = 74 - 39(0.87)^0

T(0) = 74 - 39*1

T(0) = 74 - 39

T(0) = 35

<em>Hence, the temperature at the start is 35F</em>

<em></em>

Solving (b): The room temperature

We have:

T(m) = 74 - 39(0.87)^m

To get the temperature of the room, we simply remove the exponential function.

So, we have:

Initial = 74

<em>Hence, the temperature of the room is 74F</em>

8 0
2 years ago
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