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Pani-rosa [81]
3 years ago
15

How many minutes are in the time interval from 1:22 P.M. to 5:44 P.M.​

Mathematics
1 answer:
Nikolay [14]3 years ago
4 0
Turn into military time

1:22 turns into 13:22
5:44 turns into 17:44

Then you subtract 13:22 from 17:44

You will get the answer
5hrs and 22mins

Finally convert hrs into mins and add all the mins together

You’ll get
322 mins

As your answer
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Stells [14]

Answer:

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Step-by-step explanation:

8 0
3 years ago
Hello there!
jok3333 [9.3K]

Answer:

4. dy/dx = -2

8. dy/dx = 1/2 x^(-3/2)

10/ dy/dr = 4 pi r^2

Step-by-step explanation:

4.  y = -2x+7

dy/dx = -2(1)

dy/dx = -2

8.  y = 4 - x^-1/2

 dy/dx =  - (-1/2x^ (-1/2-1)

 dy/dx = 1/2 x^(-3/2)

10.  y = 4/3 pi r^3

dy/dr = 4/3 pi  (3r^2)

dy/dr = 4 pi r^2

7 0
3 years ago
|9x-7|=|6x+3| Solve the inequality
dexar [7]

Answer:

x = 4/15 and x= 10/3

Step-by-step explanation:

|9x-7|=|6x+3|

There are two solutions, one positive and one negative.

(9x-7)=6x+3                   - (9x-7)=6x+3

We will take the positive one first

(9x-7)=6x+3

Subtract 6x from each side

(9x-6x-7)=6x-6x+3

3x -7=3

Add 7 to each side

3x-7+7 = 3+7

3x = 10

Divide by 3x/3 = 10/3

x = 10/3


Now we will take the negative solution

- (9x-7)=6x+3

Distribute the negative sign

-9x+7 = 6x+3

Add 9x to each side

-9x+9x+7 = 6x+9x+3

7 = 15x+3

Subtract 3 from each side

7-3 = 15x +3-3

4 = 15x

Divide by 15 on each side

4/15 =15x/15

4/15 =x

8 0
3 years ago
A manager is comparing wait times for customers in a coffee shop based on which employee is
anyanavicka [17]

Using the t-distribution, as we have the standard deviation for the sample, it is found that there is a significant difference between the wait times for the two populations.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, we test if there is no difference, that is:

H_0: \mu_A - \mu_B = 0

At the alternative hypothesis, it is tested if there is difference, that is:

H_1: \mu_A - \mu_B = 0

<h3>What are the mean and the standard error of the distribution of differences?</h3>

For each sample, we have that:

\mu_A = 73, s_A = \frac{2}{\sqrt{100}} = 0.2

\mu_B = 74, s_B = \frac{4}{\sqrt{100}} = 0.4

For the distribution of differences, we have that:

\overline{x} = \mu_A - \mu_B = 73 - 74 = -1

s = \sqrt{s_A^2 + s_B^2} = \sqrt{0.2^2 + 0.4^2} = 0.447

<h3>What is the test statistic?</h3>

It is given by:

t = \frac{\overline{x} - \mu}{s}

In which \mu = 0 is the value tested at the null hypothesis.

Hence:

t = \frac{\overline{x} - \mu}{s}

t = \frac{-1 - 0}{0.447}

t = -2.24

<h3>What is the p-value and the decision?</h3>

Considering a one-tailed test, as stated in the exercise, with 100 - 1 = 99 df, using a t-distribution calculator, the p-value is of 0.014.

Since the p-value is less than the significance level of 0.05, it is found that there is a significant difference between the wait times for the two populations.

More can be learned about the t-distribution at brainly.com/question/16313918

8 0
2 years ago
The difference of twice a number and 3 is -21 translated
Westkost [7]

Answer:

2x-3=-21.

2x=-21+3.

2x=-18.

x=-18/2.

x= -9.

7 0
4 years ago
Read 2 more answers
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