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IrinaVladis [17]
4 years ago
12

X to the 5th power and y to the 6th power over xy to the 2nd power ​

Mathematics
1 answer:
never [62]4 years ago
6 0

\frac{x^5y^6}{(xy)^2}

\frac{x^5y^6}{x^2y^2}

x^{5-2}y^{6-2}

x^3y^4

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