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3 years ago

A group of friends wants to go to the amusement park. They have no more than $165

Mathematics

1 answer:

Oksi-84 [34.3K]3 years ago

3 0

Answer:

17.75x + 5.25 $\leq$ 165

x $\leq$ 9

Step-by-step explanation:

The total cost can be represented by 17.75x + 5.25, where x is the number of people.

They can only spend a maximum of $165, so a less than or equal sign has to be used.

The inequality will be 17.75x + 5.25 $\leq$ 165

Now, solve for x:

17.75x + 5.25 $\leq$ 165

17.75x $\leq$ 159.75

x $\leq$ 9

So, x $\leq$ 9 is the answer, meaning 9 people or less can go to the amusement park.

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each of the 20 balls is tossed independently and at random into one of the 5 bins. let p be the probability that some bin ends u

amm1812

if p is the probability that some bin ends up with 3 balls and q is the probability that every bin ends up with 4 balls. pq is 16.

First, let us label the bins with 1,2,3,4,5.

Applying multinomial distribution with parameters n=20 and p1=p2=p3=p4=p5=15 we find that probability that bin1 ends up with 3, bin2 with 5 and bin3, bin4 and bin5 with 4 balls equals:

5−2020!3!5!4!4!4!

But of course, there are more possibilities for the same division (3,5,4,4,4) and to get the probability that one of the bins contains 3, another 5, et cetera we must multiply with the number of quintuples that has one 3, one 5, and three 4's. This leads to the following:

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In a similar way we find:

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1 year ago

It is known that 10% of the calculators shipped from a particular factory are defective. In a random sample of ten calculators,

umka2103 [35]

Answer:

0.7361

Step-by-step explanation:

In this question we have

number to be 10

Then we have a probability of 10% = 0.10

We have q = 1-p

= 1-0.10 = 0.90

Then the probability of not more than 1 being defective:

P(x=0) + p(x= 1)

(10C0 x 0.1⁰ x 0.9^10-0)+(10C1 x 0.1¹ x 0.9^10-1)

= 1 x1 x0.3487 + 10 x 0.1 x 0.3874

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This is the the required probability and this answers the question.

probability = 10 percent = 0.1

q= 1- 10percent = 90% = 0.9

n = 4

To get the required probabiltiy for this question is

P(not greater than one is defective )=P(x=0)+P(x=1)

= 4C0x(0.1)⁰x(0.9)⁴+4C1x(0.1)¹x(0.9)³

= 0.9477

The required probability is 0.9477

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