May I please get help with all the questions

Mathematics

1 answer:

bogdanovich [222]3 years ago

5 0

Answer:

1. g(3) = 1

2. (f + g)(2) = f(2) + g(2) = 2 + 3 = 5

3. f(g(4)) = 2

4. g(f(4)) = 1

5. f(f(4)) = 2

6. g(g(2)) = 1

7. base on the chart, the value 3 of g(x) can be gain only for x = 0

You might be interested in

information from research studies is sometimes taken out of context. explain why the claims of these studies might be suspect

Oxana [17]

<span>Information from research studies is sometimes taken out of context. This may happen because the researcher's interpretation of the data is being altered by their own preconceived notions, ideas, beliefs, even cultural values. To correctly interpret data, the researcher must remain completely objective.</span>

3 0

3 years ago

The size of a television is given by the length ofthe diagonal of the screen. the ratio of the height to the width of wide flat-

lbvjy [14]

The diagonal of the tv screen is given by:
d = root ((w) ^ 2 + (h) ^ 2)
Where,
w: width
h: height
In addition we have the following relationship:
h / w = 8/15
Thus,
For the width:
d = root ((w) ^ 2 + ((8/15) w) ^ 2)
For the high:
d = root (((15/8) h) ^ 2 + (h) ^ 2)
Answer:
The expressions for the width and height of a wide-screen tv in terms of the length of its diagonal are:
d = root ((w) ^ 2 + ((8/15) w) ^ 2)
d = root (((15/8) h) ^ 2 + (h) ^ 2)

5 0

4 years ago

Suppose x is a real number and epsilon > 0. Prove that (x - epsilon, x epsilon) is a neighborhood of each of its members; in

kaheart [24]

Answer:

See proof below

Step-by-step explanation:

We will use properties of inequalities during the proof.

Let $y\in (x-\epsilon,x+\epsilon)$ . then we have that $x-\epsilon$ . Hence, it makes sense to define the positive number delta as $\delta=\min\{x+\epsilon-y,y-(x-\epsilon)\}$ (the inequality guarantees that these numbers are positive).

Intuitively, delta is the shortest distance from y to the endpoints of the interval. Now, we claim that $(y-\delta,y+\delta)\subseteq (x-\epsilon,x+\epsilon)$ , and if we prove this, we are done. To prove it, let $z\in (y-\delta,y+\delta)$ , then $y-\delta$ . First, $\delta \leq y-(x-\epsilon)$ then $-\delta \geq -y+x-\epsilon$ hence $z>y-\delta \geq x-\epsilon$

On the other hand, $\delta \leq x+\epsilon-y$ then $z$ hence $z$ . Combining the inequalities, we have that $x-\epsilon$ , therefore $(y-\delta,y+\delta)\subseteq (x-\epsilon,x+\epsilon)$ as required.