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Bingel [31]
3 years ago
8

You are building a rectangular garden against the back of your house, using 80 feet of fencing. The area of the garden needs to

be greater than 400 square feet but less than 600 square feet. Which interval(s) represent possible lengths, in feet, for the horizontal edges of the garden? (0, 10) Union (30, 40) (20 minus 10 StartRoot 2 EndRoot, 20 + 10 StartRoot 2 EndRoot) (0, 20 minus 10 StartRoot 2 EndRoot) union (20 + 10 StartRoot 2 EndRoot, 40) (20 minus 10 StartRoot 2 EndRoot, 10) Union (30, 20 + 10 StartRoot 2 EndRoot)

Mathematics
2 answers:
Svetlanka [38]3 years ago
5 0

Answer:

d

Step-by-step explanation:

pantera1 [17]3 years ago
3 0

Answer: D

Step-by-step explanation:

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The time to complete the construction of a soapbox derby car is normally distributed with a mean of three hours and a standard d
TEA [102]

Answer:

The probability that it would take more than four hours to construct a soapbox derby car = 0.1587 or 15.87\%

Step-by-step explanation:

Given -

Mean (\nu )  = 3 hours

Standard deviation (\sigma  ) = 1 hours

Let X be the no of hours to construct a soapbox derby car

the probability that it would take more than four hours to construct a soapbox derby car =

P(X > 4)  = P(\frac{X - \nu }{\sigma}> \frac{4 - 3 }{1})

                = P(Z > 1)                   Put (Z = \frac{X - \nu }{\sigma})

                 =  1 -  P(Z <  1)            

                 =  1 - .8413                    Using z table

                  = 0.1587

3 0
3 years ago
Box of 15 gadgets is known to contain 5 defective gadgets if 4 gadgets are drawn at random what is the probability of finding no
baherus [9]

To solve this problem, we make use of the Binomial Probability equation which is mathematically expressed as:

P = [n! / r! (n – r)!] p^r * q^(n – r)

where,

n = the total number of gadgets = 4

r = number of samples = 1 and 2 (since not more than 2)

p = probability of success of getting a defective gadget

q = probability of failure = 1 – p

 

Calculating for p:

p = 5 / 15 = 0.33

So,

q = 1 – 0.33 = 0.67

 

Calculating for P when r = 1:

P (r = 1) = [4! / 1! 3!] 0.33^1 * 0.67^3

P (r = 1) = 0.3970

 

 

Calculating for P when r = 2:

P (r = 2) = [4! / 2! 2!] 0.33^2 * 0.67^2

P (r = 2) = 0.2933

 

Therefore the total probability of not getting more than 2 defective gadgets is:

P = 0.3970 + 0.2933

P = 0.6903

 

Hence there is a 0.6903 chance or 69.03% probability of not getting more than 2 defective gadgets.

5 0
3 years ago
Si el ∡P y el ∡Q son ángulos alternos internos, y la medida de un ángulo suplementario a uno de ellos mide 135° ,¿cuánto miden e
Hunter-Best [27]

Answer:

so sorry

Step-by-step explanation:

wish I could help but I don't know how to do it

7 0
3 years ago
What is the image of (4, -12) after a dilation by a scale factor of 1/4 centered at the origin?​
Aleonysh [2.5K]

The answer is (-1,-3)

All you have to do is divide your point by 4, since it is a fraction. if its not then multiply.

5 0
3 years ago
Lamont Gatling purchased a phone answering system for his home office. The list price was $99.86. He also purchased a 12-foot ha
Natali5045456 [20]

Answer:

$130.7086

Step-by-step explanation:

List price of phone answering system = $99.86

Handset cord = $8.95

Telephone wire = 45 cent/foot ; length = 50 feet

Rebate on phone system = $5

Store coupon =$1 of each accessory

Sales tax = 6% on final price

Price before coupon = (99.86 + 8.95 + (50*0.45)) =$131. 31

Number of accessories = 3

Total coupon = $5 + ($1 * 3) = $8

Price after coupon = final price : $131.31 - $8 = $123.31

Sales tax = 0.06 * $123.31 = $7.3986

Amount paid = $123.31 + $7.3986 = $130.7086

4 0
3 years ago
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