Answer:


A)what is the probability that the sample mean will be More than 58 pounds
P(x>58)
Formula : 
Substitute the values :


refer the z table
P(x<58)=0.5359
P(X>58)=1-P(x<58)=1-0.5359=0.4641
Hence the probability that the sample mean will be More than 58 pounds is 0.4641
B)what is the probability that the sample mean will be More than 57 pounds
P(x>57)
Formula : 
Substitute the values :


refer the z table
P(x<57)=0.5040
P(X>57)=1-P(x<57)=1-0.5040=0.496
Hence the probability that the sample mean will be More than 57 pounds is 0.496
C)what is the probability that the sample mean will be Between 55 and 57 pound
Formula : 
Substitute the values :


refer the z table
P(x<57)=0.5040
Formula : 
Substitute the values :


refer the z table
P(x<55)=0.4443
P(55<x<57)=P9x<57)-P(x<55) =0.5040-0.4443=0.0597
Hence the probability that the sample mean will be Between 55 and 57 pounds is 0.0597
D)what is the probability that the sample mean will be Less than 53 pounds
Formula : 
Substitute the values :


refer the z table
P(x<53)=0.3783
The probability that the sample mean will be Less than 53 pounds is 0.3783
E)what is the probability that the sample mean will be Less than 48 pounds
Formula : 
Substitute the values :


refer the z table
P(x<48)=0.2358
The probability that the sample mean will be Less than 48 pounds is 0.2358
Answer:
the second one 9v+36
Step-by-step explanation:
because with the way it set up it wants you to multiply 9 by everything inside of the parenthesis so 9 times v is 9v and 9 times 4 is 36 thus 9v+36 and you also take the addition symbol from inside the parenthesis.
Answer:
Max vol = 2 cubic metres
Step-by-step explanation:
Given that from a square piece of cardboard paper of area size 9 m2 , squares of the same size are cut off from each corner of the paper.
Side of the square = 3m
If squares are to be cut from the corners of the cardboard we have the dimensions of the box as
3-2x, 3-2x and x.
Hence x can never be greater than or equal to 1.5
V(x) = Volume = 
We use derivative test to find the maxima

Equate I derivative to 0

If x= 3/2 box will have 0 volume
So this is ignored
V"(1/2) <0
So maximum when x =1/2
Maximum volume
=
cubic metres
Answer:
The number of seashells he have in his collection all together is 140.
Step-by-step explanation:
Given:
Stanley has a collection of seashells. He found 35% of his collection on Florida beaches.
Stanley has 49 seashells from Florida.
Now, to find the number of seashells of his collection altogether.
Let the number of seashells all together be 
Percentage of seashells found on Florida beaches = 35%.
Number of seashells found on Florida beaches = 49.
Now, to get the number of seashells altogether we put an equation:

⇒ 
⇒ 
⇒ 
Dividing both sides by 0.35 we get:
⇒ 
Therefore, the number of seashells he have in his collection all together is 140.
Answer:
n = 1 2/5
Step-by-step explanation:
-21 + 70n = 77
Add 21 to each side
-21+21 + 70n = 77 +21
70n = 98
Divide each side by 70
70n/70 = 98/70
n =98/70
n = 70/70 +28/70
n = 1 + 2/5
n = 1 2/5