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4 years ago

Which graph represents these equations 1/3x+y=-3 and 2x+y=2

Mathematics

1 answer:

Arturiano [62]4 years ago

3 0

Answer:

Where are the graphs?????

Step-by-step explanation:

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Neeeeeed help not sure please help asap

lyudmila [28]

The correct answer is c

(it is 3 times the sum of 6 + 5 not 3 times 6 like a is suggesting)

3 0

3 years ago

Which function best shows the relationship between n and f(n)

ZanzabumX [31]

Answer: 1st graph/

f(n)=48*(0.5)^n-1

Step-by-step explanation:

Just put them in order:)

For example let's put

N=2 in 1st graph

f(2)=48*(0.5)^2-1=48*(0.5)^1=24

3 0

4 years ago

What is the effect on the graph of the function f(x) = x2 when f(x) is changed to f(x − 6)?

suter [353]

Answer:

Horizontal translation in the $+x$ direction.

Step-by-step explanation:

A function of the form $f(x)$ experiments an horizontal translation when the following substitution is applied:

$x \to x + a$ , where $a \in \mathbb{R}$

If $a > 0$ , the function is translated in the $-x$ direction, whereas $a < 0$ is the case for the function being translated in the $+x$ direction.

The effect on the graph can be defined by a composition between two function:

$f(x) = x^{2}$ , $g (x) = x-6$

$f\,\circ\,g\,(x) = (x-6)^{2}$

The resulting expression represents a horizontal translation in the $+x$ direction.

Finally, we plot $f(x)$ (red) and $f\,\circ g\,(x)$ (blue) by a graphing tool and proved the certainty of this theory.

5 0

3 years ago

Write the partial fraction decomposition fro the ration expression below

zlopas [31]

$\dfrac{5x-2}{(x-1)^2}=\dfrac a{x-1}+\dfrac b{(x-1)^2}$
$5x-2=a(x-1)+b$

Since $5x-2=5x-5+3=5(x-1)+3$ , it follows that $a=5$ and $b=3$ , so

$\dfrac{5x-2}{(x-1)^2}=\dfrac5{x-1}+\dfrac3{(x-1)^2}$

$\dfrac{x^3+x^2+x+2}{x^4+x^2}=\dfrac{x^3+x+x+2}{x^2(x^2+1)}=\dfrac ax+\dfrac b{x^2}+\dfrac{cx+d}{x^2+1}$
$x^3+x^2+x+2=ax(x^2+1)+b(x^2+1)+(cx+d)x^2$
$x^3+x^2+x+2=(a+c)x^3+(b+d)x^2+ax+b$

When $x=0$ , you find that $b=2$ . It's also clear that $a=1$ . So the remaining constants must be $1+c=1\implies c=0$ and $2+d=1\implies d=-1$ , and so you get

$\dfrac{x^3+x^2+x+2}{x^4+x^2}=\dfrac1x+\dfrac2{x^2}-\dfrac1{x^2+1}$

6 0

4 years ago

Abc congruent to pqr which of the following congruence statement is correct

rusak2 [61]

Answer:

I know the answer

Step-by-step explanation:

5 0

3 years ago