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natulia [17]
3 years ago
8

Solve for X please help I need this asap

Mathematics
2 answers:
natka813 [3]3 years ago
8 0

Answer:

f

Step-by-step explanation:

fgbdf

xenn [34]3 years ago
4 0

Answer:

x=3

Step-by-step explanation:

They are isosceles triangles and angle 2=56.  

56=53+x

x=3

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-1.3n =7.8 need help​
xxMikexx [17]

Hey there!

-1.3n = 7.8

First, you have to DIVIDE both sides by -1.3

-1.3n / -1.3 = 7.8 / -1.3

Cancel out: -1.3 / -1.3 because it gives you the value of 1

Keep: 7.8 / -1.3 because it gives us the value of n

7.8 ÷ -1.3 = -6

Thus, n = -6 ✅

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

7 0
3 years ago
Sam and bethan share £54 in the ration 5:4
Margarita [4]

Answer:

<h2>Let the common ratio b x thus the part becomes</h2><h2>=5x and 4x respectively</h2>

<h2>Thus,ATQ</h2>

<h2>5x+4x= 54</h2>

<h2>9x=54</h2>

<h2>x= 6</h2>

<h2>Sam will get is £30 (putting the value of x)</h2><h2>and Bethan will get £24</h2>
3 0
3 years ago
Verify the -(-x) = x for x= -21/31​
aliina [53]

Answer:

-3

Step-by-step explanation:

because of the root

6 0
2 years ago
3x − 15= 3x + 15<br> what is x?
Marina CMI [18]

We are given the following equation and want to find the possible values of x

3x-15=3x+15

Subtract both sides by 3x

3x-15-3x=3x+15-3x

-15=15

Now, we have this weird equation. Since -15 is NOT equal 15 and there is no other way we could have solved for x, there is no real solution to the given equation.

In other words, there is no value of x that makes the equation true.

Let me know if you need any clarifications, thanks!

~ Padoru

7 0
4 years ago
Amy is pulling a wagon with a force of 30 pounds up a hill at an angle of 25°. Give the force exerted on the wagon as a vector a
Fofino [41]

Answer:

Vector (ordered pair - rectangular form)

\vec F = (27.189,12.679)\,[lbf]

Vector (ordered pair - polar form)

\vec F = (30\,lbf, 25^{\circ})

Sum of vectorial components (linear combination)

\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force (\vec F), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

\vec F =  \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right) (1)

Vector (ordered pair - polar form)

\vec F = \left(\|\vec F\|, \theta\right)

Sum of vectorial components (linear combination)

\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j} (2)

Where:

\|\vec F\| - Norm of the vector force, in newtons.

\theta - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

\hat{i}, \hat{j} - Orthogonal axes, no unit.

If we know that \|\vec F\| = 30\,lbf and \theta = 25^{\circ}, then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf]

\vec F = (27.189,12.679)\,[lbf]

Vector (ordered pair - polar form)

\vec F = (30\,lbf, 25^{\circ})

Sum of vectorial components (linear combination)

\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N]

\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]

8 0
3 years ago
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