FUNCTION DOMAIN AND RANGE ANSWER NEEDED (25POINTS AND BRAINLIEST))

trapecia [35]

<span>Simplifying w + -11 = 1.3

Reorder the terms: -11 + w = 1.3

Solving -11 + w = 1.3

Solving for variable 'w'. Move all terms containing w to the left, all other terms to the right. Add '11' to each side of the equation. -11 + 11 + w = 1.3 + 11

Combine like terms: -11 + 11 = 0 0 + w = 1.3 + 11 w = 1.3 + 11

Combine like terms: 1.3 + 11 = 12.3 w = 12.3

Simplifying w = 12.3 <--- (Answer)

Happy studying ^-^</span>

7 0

3 years ago

Read 2 more answers

The variance can never bea.zerob.larger than the standard deviationc.negatived.smaller than the standard deviation

MrRa [10]

Answer:

c.negative

True, by definition since the variance take in count the differences around the mean squared, then we can't have a negative value for a sum of square values.

Step-by-step explanation:

We need to remember that the variance is a measure of dispersion for a dataset respect to a measure of central tendency called the mean. The mean is defined as:

$\bar x = \frac{\sum_{i=1}^n X_i}{n}$

And the population mean is given by:

$\mu= \frac{\sum_{i=1}^n X_i}{N}$

The population variance is defined by:

$\sigma^2 = \frac{\sum_{i=1}^n (X_i -\mu)^2}{N}$

And the sample variance is defined as:

$s^2= \frac{\sum_{i=1}^n (X_i -\bar x)}{n-1}$

Now if we analyze the options we have this:

a.zero

False, if all the values are the same then the mean would be the same to the values and the difference between each value and the mean would 0 and indeed the variance would be 0.

b.larger than the standard deviation

False, if the population standard deviation is $\sigma=2$ then the variance would be $\sigma^2 = 4$ and as we can see is higher than the standard deviation

c.negative

True, by definition since the variance take in count the differences around the mean squared, then we can't have a negative value for a sum of square values.

d.smaller than the standard deviation

False, if the population standard deviation is $\sigma=0.1$ then the variance would be $\sigma^2 = 0.01$ and as we can see is lower than the standard deviation

7 0

3 years ago

Find the length of CU, the triangles are similar.

Otrada [13]

Answer:

CU = 117

Step-by-step explanation:

Since the triangles are similar then the ratios of corresponding sides are equal, that is

$\frac{WC}{WU}$ = $\frac{CD}{UV}$

substituting in values to the ratios

$\frac{26}{36x-1}$ = $\frac{24}{132}$ ( cross- multiply )

24(36x - 1) = 3432 ( divide both sides by 24 )

36x - 1 = 143 ( add 1 to both sides )

36x = 144 ( divide both sides by 36 )

x = 4

CU = 36x - 1 - 26 = (36 × 4) - 27 = 144 - 27 = 117

3 0

3 years ago

Choose the correct graph of the given systems of equations. y − 2x = −1 2y − x = 4 graph of two lines intersecting at two comma

Serjik [45]

Answer:

Unfortunately, you have not provided the graphs for us to choose from. Hence, we cannot help you. Please refine your question before posting next time.

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

The employees of a company were surveyed on questions regarding their educational background (college degree or no college degre

taurus [48]

Answer: D) 0.733.

Step-by-step explanation:

Let C denotes the number of employees having college degree and S denote the number of employees are single.

We are given ,

Total = 600 , n(C)=400 , n(S)=100 , n(C∩S)=60

Then,

$n(C\cup S)=n(C)+n(S)-n(C\cap S)\\\\=400+100-60=440$

Now, the probability that an employee of the company is single or has a college degree is

$P(C\cup S)=\dfrac{n(C\cup S)}{\text{Total}}\\\\=\dfrac{440}{600}=0.733333333\approx0.733$

Hence, the probability that an employee of the company is single or has a college degree is 0.733

8 0

3 years ago

FUNCTION DOMAIN AND RANGE ANSWER NEEDED (25POINTS AND BRAINLIEST))​

FUNCTION DOMAIN AND RANGE ANSWER NEEDED (25POINTS AND BRAINLIEST))