Answer:
10/12
Step-by-step explanation:
You just have to multiply the numerator and denominator by any number, I just multiplied it by 2 and if you reduce it you still get 5/6
Step-by-step explanation:
I do hope that you understand through the steps in the attachment, if not kindly reach out!
A stuntman jumping off a 20-m-high building is modeled by the equation h = 20 – 5t2, where t is the time in seconds. A high-speed camera is ready to film him between 15 m and 10 m above the ground. For which interval of time should the camera film him?
Answer:
![1\leq t\geq \sqrt{2}](https://tex.z-dn.net/?f=1%5Cleq%20t%5Cgeq%20%5Csqrt%7B2%7D)
Step-by-step explanation:
Given:
A stuntman jumping off a 20-m-high building is modeled by the equation
-----------(1)
A high-speed camera is ready to making film between 15 m and 10 m above the ground
when the stuntman is 15m above the ground.
height
Put height value in equation 1
![15 =20-5t^{2}](https://tex.z-dn.net/?f=15%20%3D20-5t%5E%7B2%7D)
![5t^{2} =20-15](https://tex.z-dn.net/?f=5t%5E%7B2%7D%20%3D20-15)
![5t^{2} =5](https://tex.z-dn.net/?f=5t%5E%7B2%7D%20%3D5)
![t^{2} =1](https://tex.z-dn.net/?f=t%5E%7B2%7D%20%3D1)
![t =\pm1](https://tex.z-dn.net/?f=t%20%3D%5Cpm1)
We know that the time is always positive, therefore ![t=1](https://tex.z-dn.net/?f=t%3D1)
when the stuntman is 10m above the ground.
height
Put height value in equation 1
![10 =20-5t^{2}](https://tex.z-dn.net/?f=10%20%3D20-5t%5E%7B2%7D)
![5t^{2} =20-10](https://tex.z-dn.net/?f=5t%5E%7B2%7D%20%3D20-10)
![5t^{2} =10](https://tex.z-dn.net/?f=5t%5E%7B2%7D%20%3D10)
![t^{2} =\frac{10}{5}](https://tex.z-dn.net/?f=t%5E%7B2%7D%20%3D%5Cfrac%7B10%7D%7B5%7D)
![t^{2} =2](https://tex.z-dn.net/?f=t%5E%7B2%7D%20%3D2)
![t=\pm\sqrt{2}](https://tex.z-dn.net/?f=t%3D%5Cpm%5Csqrt%7B2%7D)
![t=\sqrt{2}](https://tex.z-dn.net/?f=t%3D%5Csqrt%7B2%7D)
Therefore ,time interval of camera film him is ![1\leq t\geq \sqrt{2}](https://tex.z-dn.net/?f=1%5Cleq%20t%5Cgeq%20%5Csqrt%7B2%7D)
I think the answe is 290 hours
Answer:
J
Step-by-step explanation:
h = 1.32t + 1.56
Replace t with 4 (days):
h = 1.32(4) + 1.56
Multiply:
h=5.28 + 1.56
Add:
h=6.84
The correct choice is J
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