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3 years ago

Two angles are said to be congruent if

2 answers:

6 0

Congruent means Same Side, Same Shape.
If two angles are congruent, they are to be of the same size and same shape or a fraction of it (Dilation)

Feliz [49]3 years ago

3 0

They have the same angle measure.

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The students in the Service Club are mixing paint to make a ural. The table below

maw [93]

Answer:

two different shades of what I think is pink.

1/3 is equal to 2/6 which is equal to 3/9

1/2 is equal to 2/4 which is equal to 4/8

The bolded ones are the original mixtures given.

Start with 1/3 Multiply top and bottom by 2 and you get 2/6

When you multiply top and bottom of 1/3 by by 3 you get 3/9

Use the same idea for 1/2

Step-by-step explanation:

Start with 1/3 Multiply top and bottom by 2 and you get 2/6

When you multiply top and bottom of 1/3 by by 3 you get 3/9

Use the same idea for 1/2.

4 0

3 years ago

A bad contains two red marbles, six blue marbles and seven green marbles. If two marbles are drawn out of the bag, what is the p

Luba_88 [7]

Answer:

1/105

Step-by-step explanation:

Total Marbles= 2+6+7=15

2/15 * 1/14 = 2/210 = 1/105

(It becomes 1/14 since you take out own red marble)

8 0

2 years ago

Plz help i beg!! 50 points

dedylja [7]

Answer:

63.25 sq. ft

Step-by-step explanation:

the area of fig. =

(½×8×6)+(½×3.14×5²)

= 24 + 39.25

= 63.25 sq. ft

5 0

3 years ago

Read 2 more answers

What is 7 x 4 pleez i nid help

rewona [7]

Answer: 28

Step-by-step explanation:

5 0

3 years ago

Find the derivative of <img src="https://tex.z-dn.net/?f=tan%5E%7B-1%7D%20x" id="TexFormula1" title="tan^{-1} x" alt="tan^{-1} x

sladkih [1.3K]

$\huge{\color{magenta}{\fbox{\textsf{\textbf{Answer}}}}}$

$\frak {\huge{ \frac{1}{1 + {x}^{2} } }}$

Step-by-step explanation:

$\sf let \: f(x) = { \tan }^{ - 1} x \\ \\ \sf f(x + h) = { \tan}^{ - 1} (x + h)$

$\sf f'(x) = \frac{f(x+h) - f(x) }{h}$

$\sf \implies \lim_{ h \to 0 } \frac{ { \tan }^{ - 1}(x + h) - { \tan}^{ - 1}x }{h} \\ \\ \\ \sf \implies \lim_ {h \to 0} \frac{ { \tan}^{ - 1} \frac{x + h - x}{1 + (x + h)x} }{h}$

By using

$\sf { \tan}^{ - 1} x - { \tan}^{ - 1} y = \\ \sf { \tan}^{ - 1} \frac{x - y}{1 + xy} formula$

$\sf \implies \large \lim_{h \to0 } \frac{ { \tan}^{ - 1} \frac{h}{1 + hx + {x}^{2} } }{h} \\ \\ \\ \sf \implies \large{\lim_{h \to0} } \frac{ { \tan}^{ - 1} \frac{h}{1 + hx + {x}^{2} } }{ \frac{h}{1 + hx + {x}^{2} } \times (1 + hx + {x}^{2} )} \\ \\ \\ \sf \implies \large \lim_{h \to0} \frac{ { \tan}^{ - 1} \frac{h}{1 + hx + {x}^{2} } }{ \frac{h}{1 + hx + {x}^{2} } } + \lim_{h \to0} \frac{1}{1 + hx + {x}^{2} }$

Now putting the value of h = 0

$\sf \large \implies 0 + \frac{1}{1 + 0 + {x}^{2} } \\ \\ \\ \purple{ \boxed { \implies \frac{1}{1 + {x}^{2} } }}$

6 0

2 years ago