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ira [324]
2 years ago
6

Find the value of X In the triangle below

Mathematics
2 answers:
Andreyy892 years ago
6 0
X = 5.

Pythagorus Theorem:
c^2 = b^2 + a^2
(13)^2 = (12)^2 + a^2
a = sqrt((13)^2 - (12)^2))
a = 5
pashok25 [27]2 years ago
4 0

First check attached image

By Pythagoras theorem,

ac^{2}  = {bc^{2}  + ab^{2} }

→13^{2}  = {x^{2} + 12^{2}  }

→13^{2}  = {x^{2} + 144}

→169 = x^{2} + 144

→169 - 144 = x^{2}

→25 = x^{2}

→ \sqrt{25} = x

→5 = x

Therefore, value of x is <u>5</u>

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7 0
3 years ago
HELP ME <br> solve for the right triangle
VikaD [51]

Answer:

see explanation

Step-by-step explanation:

Using the cosine and tangent ratios in the right triangle

cos41° = \frac{adjacent}{hypotenuse} = \frac{VW}{VX} = \frac{7}{VX}

Multiply both sides by VX

VX × cos41° = 7 ( divide both sides by cos41° )

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-----------------------------------------------------------------------

tan41° = \frac{opposite}{adjacent} = \frac{WX}{VW} = \frac{WX}{7}

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-------------------------------------------------------------------------

The sum of the 3 angles in a triangle = 180°

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3 0
2 years ago
Solve 2a 2 - 3a - 2 = 0<br><br> {-1/2, 2}<br> {1/2, -2}<br> {}
d1i1m1o1n [39]
Apply slip and slide
a^2-3a-4
(a-4)(a+1)
(a-2)(2a+1)

Find zeros
a-2=0
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2a+1=0
2a=-1
a=-1/2

Final answer: {-1/2, 2}
8 0
2 years ago
Read 2 more answers
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