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ira [324]
3 years ago
6

Find the value of X In the triangle below

Mathematics
2 answers:
Andreyy893 years ago
6 0
X = 5.

Pythagorus Theorem:
c^2 = b^2 + a^2
(13)^2 = (12)^2 + a^2
a = sqrt((13)^2 - (12)^2))
a = 5
pashok25 [27]3 years ago
4 0

First check attached image

By Pythagoras theorem,

ac^{2}  = {bc^{2}  + ab^{2} }

→13^{2}  = {x^{2} + 12^{2}  }

→13^{2}  = {x^{2} + 144}

→169 = x^{2} + 144

→169 - 144 = x^{2}

→25 = x^{2}

→ \sqrt{25} = x

→5 = x

Therefore, value of x is <u>5</u>

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The width of the rectangle is \frac{2}{9} unit

Step-by-step explanation:

The given is:

  • A rectangles width is 4 less than its area
  • Its length is 19 units

We need to find the width of the rectangle

Assume that the width of the rectangle is x units

∵ The area of the rectangle = length × width

∵ The width of the rectangle = x units

∵ The length of the rectangle = 19 units

∴ The area of the square = 19 × x = 19 x units²

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- Reduce the fraction by dividing up and down by -2

∴ x = \frac{2}{9}

The width of the rectangle is \frac{2}{9} unit

Learn more:

You can learn more about the rectangles in brainly.com/question/12919591

#LearnwithBrainly

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