2/3 a−7+7/18 a−5 1/6 =? 30 points if you get in right.
1 answer:
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Evaluate each of the expressions for the given values of the variables and see if the condition is met.
8000*4 +5500*6 = 65000 ≤ 75000 . . . true
52*4 +38*6 = 436 ≥ 320 . . . . . . . . . . . . . true
Yes, the company can meet both its expectations by building 4 cars and 6 motorbikes.
Of course, another way to work this is to draw the graph and see if the offered point is in the feasible region. It is.
8000*4 +5500*6 = 65000 ≤ 75000 . . . true
52*4 +38*6 = 436 ≥ 320 . . . . . . . . . . . . . true
Yes, the company can meet both its expectations by building 4 cars and 6 motorbikes.
Of course, another way to work this is to draw the graph and see if the offered point is in the feasible region. It is.
Answer:
x = 6 x = -7
Step-by-step explanation:
Subtract 12 from each side:
x^2 + x - 30 - 12 = 12 - 12
Simplify:
x^2 + x - 42 = 0
Solve with quadratic formula using both +/- after the first -1:
x =
Simplify:
x = 6
x = -7