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3 years ago

13

A triangle has one angle that measures 15 degrees, one angle that measures 44 degrees, and one angle that measures 121 degrees.

what kind of triangle is it

1 answer:

tankabanditka [31]3 years ago

6 0

Scalene triangle since all 3 interior angles are different values.

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A race car travels at a speed of 230 miles per hour. The race track on which the car is competing is 400 miles long. About how l

olga nikolaevna [1]

To solve for this we will be using the formula S = D/T

S = Speed
D = Distance
T = Time

First we need to re-arrange this formula to solve for time

T= D/S

T = 400/230

T=1.74 hours

.74 hours is close enough to .75 that we can say it is 45 minutes

So it is 1 hour and 45 minutes

7 0

3 years ago

Read 2 more answers

If f(x) = 7x+6 and g(x)=8x-4 find f(g(-2))

sp2606 [1]

Answer:

$f(g(-2))=-134$

Step-by-step explanation:

So we have the two functions:

$f(x)=7x+6\text{ and } g(x)=8x-4$

And we want to find f(g(-2)).

First, let's find g(-2):

$g(-2)=8(-2)-4$

Multiply:

$g(-2)=-16-4$

Subtract:

$g(-2)=-20$

Now, substitute:

$f(g(-2))=f(-20)$

Now, find the value of f(-20):

$f(-20)=7(-20)+6$

Multiply:

$f(-20)=-140+6$

Add:

$f(-20)=-134$

So:

$f(g(-2))=-134$

And we're done!

5 0

3 years ago

(12 - 8)3 – 24 x 2<br> Plz help me

yawa3891 [41]

La réponse est -36
love u <333

3 0

3 years ago

Solving Quadratic Equations using the Square Root Property

Afina-wow [57]

Answer:

$x = -2$ or $x = -5$

Step-by-step explanation:

You need to complete the square before you can take the square root of both sides.

$x^2 + 7x + 10 = 0$

Subtract 10 from both sides.

$x^2 + 7x = -10$

To complete the square, you need to add the square of half of the x-term coefficient to both sides.

The x-term coefficient is 7. Half of that is 7/2. Square it to get 49/4. Now we add 49/4 to both sides of the equation.

$x^2 + 7x + \dfrac{49}{4} = -10 + \dfrac{49}{4}$

$(x + \dfrac{7}{2})^2 = -\dfrac{40}{4} + \dfrac{49}{4}$

$(x + \dfrac{7}{2})^2 = \dfrac{9}{4}$

Now we use the square root property, if

$x^2 = k$ , then

$x = \pm \sqrt{k}$

$x + \dfrac{7}{2} = \pm \sqrt{\dfrac{9}{4}}$

$x + \dfrac{7}{2} = \pm \dfrac{3}{2}$

$x + \dfrac{7}{2} = \dfrac{3}{2}$ or $x + \dfrac{7}{2} = -\dfrac{3}{2}$

$x = -\dfrac{4}{2}$ or $x = -\dfrac{10}{2}$

$x = -2$ or $x = -5$

5 0

3 years ago

1/(x+4)(x-2)(x-5) excluded values

UNO [17]

Answer:

see explanation

Step-by-step explanation:

The excluded values are any values of x that make the function undefined

Given

$\frac{1}{(x+4)(x-2)(x-5)}$

The denominator of the rational function cannot be zero as this would make it undefined. Equating the denominator to zero and solving gives the values that x cannot be.

(x + 4)(x - 2)(x - 5) = 0

Equate each factor to zero and solve for x

x + 4 = 0 ⇒ x = - 4

x - 2 = 0 ⇒ x = 2

x - 5 = 0 ⇒ x = 5

x = - 4, x = 2, x = 5 are the excluded values

4 0

3 years ago