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Novosadov [1.4K]
4 years ago
7

`DeltaABC` is congruent to `DeltaADC`. If the square ABCD is dilated by a factor of 2 to form A'B'C'D', what is the ratio of the

area of A'B'C'D' to the area of ABCD?
Mathematics
1 answer:
Igoryamba4 years ago
3 0

The square is dilated by a factor of 2 to form A'B'C'D'.

Which mean the new square sides will be twice as much as the old square.

Let the side length of the square ABCD = x

∴ The side length of the square A'B'C'D' =2x

∵ The area of the square = (side length)²

Area of ABCD = x²

Area of A'B'C'D'= (2x)² = 4x²

∴ Area of A'B'C'D' :  Area of ABCD = 4x² : x² = 4 : 1

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