Option C
Math teacher would need to buy 130 prizes
<em><u>Solution:</u></em>
Given that,
Math teacher currently has 109 students and the box has 88 prizes in it
The math teacher likes to keep at least twice as many prizes in the box as she has students
So, she wants the number of prizes to be twice the number of students
Therefore,
number of prizes = 2 x 109 students
number of prizes = 2 x 109 = 218 prizes
The box has 88 prizes in it
Therefore, number of prizes she would need to buy is:
⇒ 218 - 88 = 130
Thus she would need to buy 130 prizes
Answer:
- (0, 4)
- (-1, 16/ 3)
- (-9/ 2, 10)
Step-by-step explanation:
In an ordered pair the term before the comma is the x variable and the term after the comma is the y variable.
1.
4x + 3y = 12 . . . . . .(0, _)
here were given the x variable
finding the other term
4× 0 + 3y = 12
3y = 12
y = 4
therefore the ordered pair is <u>(0, 4) </u>
2.
. . . . . . . (-1, _)
here were given the x variable
4 × -1 + 3y = 12
3y = 12 + 4
3y = 16
y = 16/ 3
ordered pair is <u>(-1, 16/ 3)</u>
3.
. . . . . . . . (_, 10)
here were given the y variable
finding the other term
4x + 3 × 10 = 12
4x + 30 = 12
4x = 12 - 30
4x = -18
dividing both sides by 2
2x = -9
x = -9/ 2
ordered pair is<u> (-9/ 2, 10)</u>
Answer:
SOLUTION: X=5
Step-by-step explanation:
x=5
y=27
vertical input= (0, 1/9)
Hope that helps!
Probably A I am not really sure I am trying sorry if it is wrong
