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OLga [1]
3 years ago
13

Which phrase SIgnals a compare and-contrast text structure O as a result betore long for this reason on the other hand​

Mathematics
1 answer:
Shalnov [3]3 years ago
7 0

Answer:

D. On the other hand.

Step-by-step explanation:

As a result, before long, and for this reason would be cause and effect. On the other hand is the only remaining option.

You might be interested in
△ABC≅△DEF, BC=4x−12, and EF=−3x+16. Find x and EF.
kirill [66]

x = 4 and EF = 4 ⇒ 3rd answer

Step-by-step explanation:

If two triangles are congruent, then

1. Their corresponding sides are equal

2. Their corresponding angles are equal

3. Their areas and perimeters are equal

∵ △ ABC ≅ △ DEF

∴ AB ≅ DE

∴ BC ≅ EF

∴ AC ≅ DF

∵ BC = 4 x - 12

∵ EF = -3 x + 16

∵ BC = EF

∴ 4 x - 12 = -3 x + 16

Let us solve the equation to find x

∵ 4 x - 12 = -3 x + 16

- Add 3 x for both sides

∴ 7 x - 12 = 16

- Add 12 to both sides

∴ 7 x = 28

- Divide both sides by 7

∴ x = 4

Substitute the value of x in the expression of EF

∵ EF = -3 x + 16

∵ x = 4

∴ EF = -3(4) + 16 = -12 + 16

∴ EF = 4

x = 4 and EF = 4

Learn more:

You can learn more about congruence of Δs in brainly.com/question/3202836

#LearnwithBrainly

3 0
2 years ago
Sum of -6x^2-1 and x+9
Bumek [7]

Answer:

-6x^2+x+8

Step-by-step explanation:

9+-1=8

3 0
2 years ago
Read 2 more answers
A company compiles data on a variety of issues in education. In 2004 the company reported that the national college​ freshman-to
nasty-shy [4]

Answer:

1) Randomization: We assume that we have a random sample of students

2) 10% condition, for this case we assume that the sample size is lower than 10% of the real population size

3) np = 500*0.66= 330 >10

n(1-p) = 500*(1-0.66) =170>10

So then we can use the normal approximation for the distribution of p, since the conditions are satisfied

The population proportion have the following distribution :

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

And we have :

\mu_p = 0.66

\sigma_{p}= \sqrt{\frac{0.66(1-0.66)}{500}}= 0.0212

Using the 68-95-99.7% rule we expect 68% of the values between 0.639 (63.9%) and 0.681 (68.1%), 95% of the values between 0.618(61.8%) and 0.702(70.2%) and 99.7% of the values between 0.596(59.6%) and 0.724(72.4%).

Step-by-step explanation:

For this case we know that we have a sample of n = 500 students and we have a percentage of expected return for their sophomore years given 66% and on fraction would be 0.66 and we are interested on the distribution for the population proportion p.

We want to know if we can apply the normal approximation, so we need to check 3 conditions:

1) Randomization: We assume that we have a random sample of students

2) 10% condition, for this case we assume that the sample size is lower than 10% of the real population size

3) np = 500*0.66= 330 >10

n(1-p) = 500*(1-0.66) =170>10

So then we can use the normal approximation for the distribution of p, since the conditions are satisfied

The population proportion have the following distribution :

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

And we have :

\mu_p = 0.66

\sigma_{p}= \sqrt{\frac{0.66(1-0.66)}{500}}= 0.0212

And we can use the empirical rule to describe the distribution of percentages.

The empirical rule, also known as three-sigma rule or 68-95-99.7 rule, "is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ)".

On this case in order to check if the random variable X follows a normal distribution we can use the empirical rule that states the following:

• The probability of obtain values within one deviation from the mean is 0.68

• The probability of obtain values within two deviation's from the mean is 0.95

• The probability of obtain values within three deviation's from the mean is 0.997

Using the 68-95-99.7% rule we expect 68% of the values between 0.639 (63.9%) and 0.681 (68.1%), 95% of the values between 0.618(61.8%) and 0.702(70.2%) and 99.7% of the values between 0.596(59.6%) and 0.724(72.4%).

8 0
3 years ago
Using the algebraic expression 4n + 6, what is the greatest whole-# value of n that will give you a result less than 100?
Whitepunk [10]
A) 22
4 (22) + 6
88 + 6 = 94

B) 23
4 (23) + 6
92 + 6 = 98

C) 24
4 (24) = 96
96 + 6 = 102

So the answer is B because it is the highest value that can be put into the equation without raising the number to above 100
6 0
3 years ago
Ms. Cohen is buying supplies for her kindergarten class room. she can spend at most $30. she wants to buy boxes of crayons that
ale4655 [162]

Answer:

15

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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