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AlexFokin [52]
4 years ago
10

A new park in the shape of a hexagon will have 66 sides of equal length. On a scale drawing, the coordinates of the vertices of

the park are: (6.5,5)6.5,5, (18.5,0)18.5,0, (6.5,-5)6.5,-5, (-6.5,-5)-6.5,-5, (-18.5,0)-18.5,0, and (-6.5,5)-6.5,5. How long is each side of the park?
Mathematics
2 answers:
solniwko [45]4 years ago
8 0
The answer is: 13 units.  
__________________________________________________
Each side of the park is 13 units long.
_______________________________
(Assuming hexagonal shape will have 6 (SIX) sides of equal length).
_________________________________________________
Explanation:
__________________________
Let us assume you meant to write that the: "...new park, in the shape of hexagon, will have 6 (six) side of equal length."
_________________________________________
From the coordinates given, we can infer that this is a "regular" hexagon. 
_______________
Here is one way to solve the problem:  Find the length of ONE side of the hexagon.
_____________________
Let us choose the following coordinates: (18,0), and (6.5, 5).  Let the distance between these points , which would equal ONE side of our hexagon, represent "c", the hypotenuse of a right triangle. We want to solve for this value, "c".
_____________________
Let the distance on the x-axis, from (6.5, 0) to (18.5, 0);  represent "b", one side of a right triangle.  
   → We can solve for "b" ;  → b = 18.5 - 6.5 ;  → b = 12 .
___________________________________________________'
Let the distance from (6.5, 0) to (6.5, 5) ; represent "a"; the remaining side of the right triangle.
__________________
 → a = y₂ - y₁ = 5 - 0 = 5 ; 
________________________________________________
{Note: We choose the particular coordinates, including "(6.5, 0)", because the distances between the coordinates chosen form a "right triangle";  (with "c", representing a "hypotenuse", or "slanted line segment"; which would be also be "ONE line segment of the given regular hexagon", which is our answer, because each line segment is the same values, so we only have to find the value of ONE line segment, or side, of the hexagon.).
    When considering the given coordinates: "(6.5, 5)", and "(18.5, 0)", a "right triangle" can be formed at the coordinate, "(6.5, 0),

By choosing this particular letters (variables) to represent the sides of a "right triangle", we can solve for the "hypotenuse, "c", using the Pythagorean theorem for the sides of a right triangle: 
______________________
 → a² + b² = c² ; in which "c" represents the hypotenuse of the right triangle
and "a" represents the length of one of the other sides; and "b" represents the length of the remaining side. (Note: All triangles have three sides).
_____________________________
We have: a = 5 ;  b = 12 ; → Solve for "c" ; 
______________________________________
 → a² + b² = c² ;  ↔  c² = a² + b²  ; Plug in the known values for "a" & "b" ;
___________________________________
→ c² = a² + b² ;  → c² = 5² + 12² ;

→ c² = 25 + 144 = 169 ;   →  c²  = 169 ;
_________________________________________
→ Take the square root of each side; to isolate "c" on one side of the equation; and to solve for "c" ;
______________________________
 →  c²  = 169 ;  √(c²) = √(169) ;  →  c = ± 13; 
 
 → ignore the negative value; since the side of a polygon cannot be a negative number; 
________________________________
 →  c = 13 ; The answer is: 13 units.
________________________________
stiv31 [10]4 years ago
3 0
1) Take 2 points which are on the same horizontal line: they are for example:
(6.5,5) and <span>(-6.5,5). Both are 5 units above X-axis as their y=5.
2) Then estimate distance btw x coordinate. That's the difference btw positive 6.5 and negative 6.5. That's 13 units. :)  That's how long each side is :)


You can do same with the pair of </span><span>(6.5,-5) and (-6.5,-5) - they belong to the line y=-5 (parallel to x-axis) and distance btw 6.5 and -6.5 is again 13 units </span>
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Ur answer will be marked as brainliest...
Julli [10]

Answer:

92.75 cm^2

Step-by-step explanation:

Area of triangle ADC

= (1/2)×4.5×12 = 27

Area of triangle ACB

=(1/2)×12×5 = 30

Find AB using pythagoras theorem on triangle ABC:

AB^2 = 5^2 + 12^2 = 25 + 144

AB^2 = 169

AB = 13cm

Area of triangle AGB

= (1/2)×13×5.5 = 35.75

Total area = sum of the areas of the 3 triangles found above

= 27 + 30 + 35.75 = 92.75 cm^2

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