Excel expects a + or = sign before math calculations.
Also, for arguments of functions (such as sqrt), parentheses "()" are used. Brackets "[]" are not acceptable.
That leaves only one remaining option.
It is 102.5. You made it kind of confusing at first by putting the divisor first in your question then putting your dividend, but I understand what you meant.
When the population mean and standard deviation are known, you use the standard normal distribution
<h3>How to determine the distribution?</h3>
There are several probability distributions; these include
- Normal distribution
- Poisson distribution
- Chi square distribution
- Binomial distribution
- Etc
Of all these distribution, only the standard normal distribution can be used when the population mean and standard deviation are known,
Note that it is also referred to as the z-distribution
Read more about probability distributions at:
brainly.com/question/24756209
Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.
1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.
According to this theorem,

Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then

Take positive value x. You get

2. According to the previous theorem,

Then

Answer: 
This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then

This means that you cannot find solutions of this equation. Then CD≠2 cm.
Answer:
18
Step-by-step explanation: