The setup boxes in the synthetic division are (b)
<h3>How to determine the setup boxes?</h3>
The dividend is given as:
x^3 + 4x^2 + x - 6
The divisor is given as:
x - 2
Set the divisor to 0
x - 2 = 0
Solve for x
x = 2
Remove the variables in the dividend
1 + 4 + 1 - 6
Remove the arithmetic signs
1 4 1 - 6
So, the setup is:
2 | 1 4 1 - 6
Hence, the setup boxes are (b)
Read more about synthetic division at:
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I think it is not possible to find a certain equation from just a given points, it must have more given information because there is a lot of parabola pass throw (-1,1).
Answer:
y=4, x=8
Step-by-step explanation:
system:
x+y = 12, x=2y
convert to 1 variable, simplify:
2y+y=12
3y=12
y=4
x=2y=4*2=8
Use these equations when converting polar equations to parametric equations:
We know that 
, so substitute that into both equations for x and y.
Now, replace 
with any variable that you want to represent the parametric equations in. I'll use the standard variable, 
Thus, represented in parametric form is:
Let me know if you need any clarifications, thanks!
~ Padoru
