3 years ago

Help me on this math problem

Mathematics

1 answer:

Anon25 [30]3 years ago

4 0

Answer:

D: t = u/9 + 7 (that is simplified all of the way) for your case it is t = u + 63/9 so D

Explanation:

Just ask if you need an explanation. Also, does anyone do LD debate?

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Someone please help me out with this, thank you!

zaharov [31]

Answer:

(2,-2)

Step-by-step explanation:

the x-intercept is 2

and y-intercept is-2

x-intercept is when you have a number comma 0 e.g 3,0. 2,0

y-intercept is when u have 0 comma a number e.g 0,2 0,-5

3 0

2 years ago

Perform the operation (5x^2 – 9) + (-10x + 7)

Stels [109]

Answer:

5x^2−10x−2

Step-by-step explanation:

I hope this is what you are looking for I just added (5x^2 – 9) + (-10x + 7)

8 0

2 years ago

Read 2 more answers

Θ is an acute angle and cosecant theta equals nine halves commacscθ= 9 2, find secant ((pi over 2) minus theta) .sec π 2−θ. do n

Ronch [10]

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8 0

3 years ago

The width of a rectangle, in feet, is represented by (3x-1). The length of the rectangle, in feet, is represented by (1.5x+3). F

bogdanovich [222]

Answer: 4.5x + 2

Explanation:

Sum of length and width = (3x-1)+(1.5x+3)
= 3x - 1 + 1.5x + 3
= 4.5x + 2

7 0

2 years ago

Which expression is equivalent

RUDIKE [14]

Given expression is

$\sqrt[4]{\frac{16x^{11}y^8}{81x^7y^6}}$

Radical is fourth root

first we simplify the terms inside the radical

$\frac{x^{11}}{x^7}=x^4$

$\frac{y^(8)}{y^6}=y^2$

So the expression becomes

$\sqrt[4]{\frac{16x^4y^2}{81}}$

Now we take fourth root

$\sqrt[4]{16} = 2$

$\sqrt[4]{81} = 3$

$\sqrt[4]{x^4} = x$

We cannot simplify fourth root (y^2)

After simplification , expression becomes

$\frac{2x\sqrt[4]{y^2}}{3}$

Answer is option B

7 0

3 years ago