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3 years ago

How to find the slope

Mathematics

1 answer:

rosijanka [135]3 years ago

3 0

Make A triangle useiing the two points count x first and put it on top then y and do the same determine if it is negative or positive

Hope this helps

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The owner of the Outdoor Furniture Center decides to use the 120% markup. At the end on

lana66690 [7]

Answer: The total price of a bench is 1.008x.

Step-by-step explanation:

Since we have given that

Let the cost price be 'x'.

Mark up % = 120%

So, Mark up value would be

$\dfrac{120}{100}x\\\\=1.20x$

Discount % = 20%

Amount of discount is given by

$\dfrac{20}{100}\times 1.2x\\\\=0.2\times 1.2x\\\\=0.24x$

So, it becomes,

Amount after discount is given by

$1.2x-0.24x\\\\=0.96x$

Sales tax = 5%

Amount of sales tax would be

$\dfrac{100+5}{100}\times 0.96x\\\\=\dfrac{105}{100}\times 0.96x\\\\=1.05\times 0.96x\\\\=1.008x$

Hence, the total price of a bench is 1.008x.

6 0

4 years ago

Any good mathematicians out there?! In need of help Brainliest + POINTS

Zarrin [17]

Answer:

1199 $

Step-by-step explanation:

3297+365=3662

1280+270+325+153+300+50+35= 2413

3662-2413=1249$

i hope u understand

3 0

4 years ago

Read 2 more answers

18 miles is what percent of 24 miles?

Gekata [30.6K]

Answer:

3/4

Cause there are 3 sixes in 18 and 4 sixes in 24

4 0

3 years ago

What is z(4)+z(4)+z(4)+z(4)

romanna [79]

16z because you’re adding 4z four times

8 0

3 years ago

Find all roots: x^3 + 7x^2 + 12x = 0 Show all work and check your answer.

Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

Solution:

We have been given a cubic polynomial.

$x^{3}+7 x^{2}+12 x=0$

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

$x^{3}+7 x^{2}+12 x=0$

$x\left(x^{2}+7 x+12\right)=0$ ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

$x^{2}+7 x+12=0$

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

$\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}$

Therefore, the two roots are:

$\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}$

And,

$\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}$

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0

3 years ago