Let student tickets be s and adult tickets be a. The number of tickets sold of both adult and student then is s + a = 396. If each student ticket costs $3, then we represent the money equation by tacking the dollar amount onto the ticket. 3s is the cost of one student ticket. 4a is the cost of an adult ticket. The total money from the sales of both is 4a + 3s = 1385. We now have a system of equations we can solve for a and s. If s+a=396, then s = 396-a. We will sub that into the second equation to get 4a + 3(396-a) = 1385. Distributing we have 4a+1188-3a=1385. a = 197. That means there were 197 adult tickets sold. If s + a = 396, then s + 197 = 396 and s = 199. 197 adult tickets and 199 student tickets. There you go!
Answer:
x = 66
Step-by-step explanation:
For a set of N numbers:
{x₁, x₂, ..., xₙ}
The mean can be calculated as:
In this case we have the data set:
{98, 122, 104, 115, 107, x}
And I assume that we want to have the mean = 102.
So we have a set of 6 numbers, the mean of this set will be:
We need to solve this equation for x.
If we multiply both sides by 6, we get:
(98 + 122 + 104 + 115 + 107 + x) = 102*6 = 612
546 + x = 612
x = 612 - 546 = 66
x = 66
Answer:
I wish I had the answer for you since I feel the same way when I have a teast n iono the answer its soo stressing hope you have u get a good grade by finding the answer some how.
SRRY
