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3 years ago

What is the solution to this equation?

Mathematics

2 answers:

Usimov [2.4K]3 years ago

7 0

-0.5 n^2=-18
n^2= 36
n= sqrt (36)=6 or -6

Hope this can help.

jeka57 [31]3 years ago

5 0

Answer:

n=±6

Step-by-step explanation:

-1/2 n²+18=0

-1/2 n² =-18

-n²=-36

n²=36

n=√36

n=±6

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3 Write a numerical expression to model the words. Subtract 1 from the product of 4 and 5.

umka21 [38]

Answer:

Hello!

After reading the question you have provided I have come up with the correct numerical expression:

4x5-1

Step-by-step explanation:

To come up with this solution you need to keep in mind some of the terminoloy being used.

The word "subtract" comes from the action of subtraction

The word "product" comes from the action of multiplication

Thus, using those terminologies correctly, you can then deduce that when the question says "the product of 4 and 5" means "multiplying 4 and 5 together".

So you get the first part being 4x5

Then, you add in the last part of "subract 1" from the "product of 4 and 5":

4x5-1

<em>Remember to keep in mind the rule of "PEMDAS"</em>

You always need to keep the multiplication portion of the equation in front of any subtraction, or addition in any given equation.

7 0

2 years ago

Read 2 more answers

Dale drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took hours. When Dale drove hom

IrinaK [193]

Dale drove to the mountains last weekend. there was heavy traffic on the way there, and the trip took 7 hours. when dale drove home, there was no traffic and the trip only took 5 hours. if his average rate was 18 miles per hour faster on the trip home, how far away does dale live from the mountains? do not do any rounding.

Answer:

Dale live 315 miles from the mountains

Step-by-step explanation:

Let y be the speed of Dale to the mountains

Time taken by Dale to the mountains=7 hrs

Therefore distance covered by dale to the mountain = speed × time = 7y ......eqn 1

Time taken by Dale back home = 5hours

Since it speed increased by 18 miles per hour back home it speed = y+18

So distance traveled home =speed × time = (y+18)5 ...... eqn 2

Since distance cover is same in both the eqn 1 and eqn 2.

Eqn 1 = eqn 2

7y = (y+18)5

7y = 5y + 90

7y - 5y = 90 (collection like terms)

2y = 90

Y = 45

Substitute for y in eqn 1 to get distance away from mountain

= 7y eqn 1

= 7×45

= 315 miles.

∴ Dale leave 315 miles from the mountains

4 0

3 years ago

2b^2+4b–2=0 what is the answer?

s2008m [1.1K]

$2b^2+4b-2=0\\
2(b^2+2b-1)=0\\
2(b^2+2b+1-2)=0\\
2((b+1)^2-2)=0\\
2(b+1)^2-4=0\\\
2(b+1)^2=4\\\
(b+1)^2=2\\
b+1=-\sqrt2 \vee b+1=\sqrt2\\
b=-1-\sqrt2 \vee b=-1+\sqrt2

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