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CaHeK987 [17]
3 years ago
11

Equipment was purchased at a cost of $52,000. It had an estimated useful life of seven years and a residual value of $3,000. Ass

uming the equipment was sold at the end of Year 6 for $14,000, which of the following will be included in the journal entry? (Assume the straight-line depreciation method.)
Mathematics
1 answer:
Kipish [7]3 years ago
4 0

Answer:

a debit to Accumulated Depreciation—Equipment

Step-by-step explanation:

we know that

Depreciation/year=(Cost-Residual value)/Useful life

put values

=(52000-3000)/7=$7000

Hence book value as on date of sale=52000-(7000*6)=$10000

Hence gain on sale=(14000-10000)=$4000

Hence the journal is :

Cash a/c..Dr$14000

Accumulated Depreciation..Dr$42000

To equipment $52000

To gain on sale $4000

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Answer:

x= -1

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3 years ago
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3 years ago
5/8(x-1/3)=5/12 can someone help me figure out what x is?
eimsori [14]
Solve for x:(5 (x - 1/3))/(8) = 5/12
Put each term in x - 1/3 over the common denominator 3: x - 1/3 = (3 x)/3 - 1/3:(5 (3 x)/3 - 1/3)/(8) = 5/12
(3 x)/3 - 1/3 = (3 x - 1)/3:(5 (3 x - 1)/3)/(8) = 5/12
3×8 = 24:(5 (3 x - 1))/24 = 5/12
Multiply both sides of (5 (3 x - 1))/24 = 5/12 by 24/5:(24×5 (3 x - 1))/(5×24) = (24×5)/(5×12)
(24×5)/(5×12) = (24×5)/(5×12):(24×5 (3 x - 1))/(5×24) = (24×5)/(5×12)
(24×5 (3 x - 1))/(5×24) = (5×24)/(5×24)×(3 x - 1) = 3 x - 1:3 x - 1 = (24×5)/(5×12)
(24×5)/(5×12) = 5/5×24/12 = 24/12:3 x - 1 = 24/12
The gcd of 24 and 12 is 12, so 24/12 = (12×2)/(12×1) = 12/12×2 = 2:3 x - 1 = 2
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3 0
3 years ago
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Alik [6]

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