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CaHeK987 [17]
3 years ago
11

Equipment was purchased at a cost of $52,000. It had an estimated useful life of seven years and a residual value of $3,000. Ass

uming the equipment was sold at the end of Year 6 for $14,000, which of the following will be included in the journal entry? (Assume the straight-line depreciation method.)
Mathematics
1 answer:
Kipish [7]3 years ago
4 0

Answer:

a debit to Accumulated Depreciation—Equipment

Step-by-step explanation:

we know that

Depreciation/year=(Cost-Residual value)/Useful life

put values

=(52000-3000)/7=$7000

Hence book value as on date of sale=52000-(7000*6)=$10000

Hence gain on sale=(14000-10000)=$4000

Hence the journal is :

Cash a/c..Dr$14000

Accumulated Depreciation..Dr$42000

To equipment $52000

To gain on sale $4000

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Factor by GCF
madam [21]

Answer:

10x^(2)-4x

Step-by-step explanation:

8 0
3 years ago
Ramiro earns $20 per hour during the week and $30 per hour for overtime on the weekends. One week Ramiro earned a total of $650.
nika2105 [10]

Answer:

Week=25 Hours

Weekend= 5 Hours

Step-by-step explanation:

So we need to use the info they gave us and create two equations. Firstly we know how much he gets paid per hour during the week (x) and how much he gets paid on the weekend (y).

$20x+$30y=$650

We get this because we know the combined rates he is paid times the hours should add up to the amount he earned.

The next equation will be made off of the information that he worked 5 times as many hours during the week as on the weekend. This tells us that we will take the weekend hours (y) and multiply them by 5 in order to get the week hours (x).

x=5y      Now, since we have one variable by itself, we can plug it in for x in the first equation.

20(5y)+30y=650    Our first step here is to distribute the 20 to the 5y in order to eliminate the parenthesis.

100y+30y=650    Next add the like terms together (100y+30y).

Now all we have to do to find y is divide by 130 on both sides to get y alone.

130y=650  

________

130     130

y=5             Now to solve for x we just plug our y value into one of the equations above. I'm going to use the second equation.

x=5(5)

x=25      

3 0
3 years ago
Find the slope given the following ordered <br><br> 2,-3 and 6,-13
saw5 [17]

You would have to use this equation : y2-y1/x2-x1 = slope

So it would be -13 +3/6-2= -10/4

Simplify it and you get : -5/2

Slope is -5/2

7 0
3 years ago
Read 2 more answers
M &lt; TYV=64°<br><br> What is m<br> A.116°<br> B.90°<br> C.26°<br> D.64°
solmaris [256]
My answer to this question C
4 0
3 years ago
Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be
Oksana_A [137]
<h2>Hello!</h2>

The answers are:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

<h2>Why?</h2>

To calculate the speed of the cars, we need to write two equations, one for each car, in order to create a relation between the two speeds and be able to calculate one in function of the other.

So,

Tet be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

x_{FirstCar}=x_o+v*t

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

x_{SecondCar}=x_o+(v+14mph)*t

Now, from the statement that both cars met after 2 hours and 45 minutes, and the distance between to cover (between A and B) is 264 miles,  so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph

Then, since we know that they covered a combined distance equal to 264 miles in 2 hours + 45 minutes, we have:

2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours

Writing the equation:

264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph

So, the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph

We have that the speed of the second car is equal to 55 mph.

Hence, the answers are:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

Have a nice day!

7 0
3 years ago
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