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FromTheMoon [43]
3 years ago
7

19

Mathematics
1 answer:
Nikolay [14]3 years ago
7 0

Answer: 1 year

Step-by-step explanation:

510,000 × .08 = 40,800

40,800 is way more then 5k so yeah 1 year

But realistically less than that.

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The lunch special at Scott's Restaurant is a sandwich, a drink and a dessert. There are 3 sandwiches, 1 drink, and 2 desserts to
mash [69]

Answer:

24 for being able to not have one, 6 for having one of each

Step-by-step explanation:

multiplication

with the option of none

4*2*3=24

without the option of none

3*1*2=6

4 0
2 years ago
Please answer this geometry proof as soon as possible!
Kay [80]

Answer:

In order to get an answer you have to post a question.

Step-by-step explanation:

6 0
3 years ago
List all the pairs of integers with a product of 36. then find the pair whose sum is 20
RoseWind [281]
This is an excellent practice for the solution of quadratic equations.

1*36=36  => (1,36)
2*18=36  => (2,18)
3*12=36  => (3,12)
4*9=36   => (4,9)
6*6=36   => (6,6)
9*4=36   => (9,4)
12*3=36  => (12,3)
18*2=36  => (18,2)
36*1=36  => (36,1)

We can see that the sum decreases until the two factors are close (or equal) and then increases again.

The pair of integers with a sum of 20 is therefore (2,18) or (18,2).
4 0
4 years ago
Read 2 more answers
A box of Munchkins contains chocolate and glazed donut holes. If Jacob ate 2 chocolate
neonofarm [45]

Answer:

24 munchkins.

Step-by-step explanation:  

Let C be the number of chocolate and D be number of glazed donut holes in the original box.

We are told if Jacob ate 2 chocolate  munchkins, then 1/11 of the remaining Munchkins would be chocolate. We can represent this information as:

C-2=\frac{1}{11}*(C+D-2)...(1)

We are also told if he instead added 4  glazed Munchkins to the original box, 1/7 of the Munchkins would be chocolate. We can represent this information as:

C=\frac{1}{7}*(C+D+4)...(2)

Upon substituting C's value from equation (2) in equation (1) we will get,

\frac{1}{7}*(C+D+4)-2=\frac{1}{11}*(C+D-2)

Let us have a common denominator on right side of equation.

\frac{1}{7}*(C+D+4)-\frac{7*2}{7}=\frac{1}{11}*(C+D-2)

\frac{C+D+4-14}{7}=\frac{1}{11}*(C+D-2)

Multiplying both sides of our equation by 7, we will get,

7*\frac{C+D-10}{7}=7*\frac{1}{11}*(C+D-2)

C+D-10=\frac{7}{11}*(C+D-2)  

Multiplying both sides of our equation by 11, we will get,

11*(C+D-10)=11*\frac{7}{11}*(C+D-2)  

11*(C+D-10)=7*(C+D-2)

11C+11D-110=7C+7D-14

11C-7C+11D-7D=-14+110  

4C+4D=96

4(C+D)=96  

(C+D)=\frac{96}{4}

(C+D)=24

Therefore, the total number of Munchkins in original box is 24.

3 0
3 years ago
A rectangular painting measures 12 inches by 14 inches and contains a frame of uniform width around the four edges the perimeter
Amiraneli [1.4K]

Answer: 6in width

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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