Answer:
#include<iostream>
using namespace std;
int lcm(int m, int n) {
int a;
a = (m > n) ? m: n;
while (true) {
if (a % m == 0 && a % n == 0)
return a;
++a;
}
}
int gcd(int m, int n) {
int r = 0, a, b;
a = (m > n) ? m : n;
b = (m < n) ? m : n;
r = b;
while (a % b != 0) {
r = a % b;
a = b;
b = r;
}
return r;
}
int main(int argc, char **argv) {
cout << "Enter the two numbers: ";
int m, n;
cin >> m >> n;
cout << "The LCM of two numbers is: " << lcm(m, n) << endl;
cout << "The GCD of two numbers is: " << gcd(m, n) << endl;
return 0;
}
Explanation:
It's easy you need to use function for decimal in binary.
binary STD;
int STD_no;
STD=STD_No.ToBinary
Microsoft company was founded in 1975
Answer:
D
Explanation:
All three of A, B and C are required to harden a host. Thus, All of the above makes the best option.
Hardening simply refers to making your data impossible to be penetrated. More like bulletproof.
To do this, ensure measures like
- Regular Program cleanup
- Patches management
- service pack installation
- service or usage policies
...among others.
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