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andreyandreev [35.5K]
3 years ago
8

Your wireless network consists of multiple 802.11n access points that are configured as follows: SSID (hidden): CorpNet Security

: WPA2-PSK using AES Frequency: 5.7 GHz Bandwidth per channel: 20 MHz This network is required to support an ever-increasing number of devices. To ensure there is sufficient capacity, you want to maximize the available network bandwidth. What should you do
Computers and Technology
1 answer:
nasty-shy [4]3 years ago
6 0

Answer:

double the bandwidth assigned per channel to 40 MHz

Explanation:

The best way of doing this would be to double the bandwidth assigned per channel to 40 MHz. This will make sure that the capacity is more than sufficient. This is simply because the bandwidth of a channel represents how much information can pass through the channel at any given second, the larger the channel, the more information/data that can pass at the same time. Therefore, if 20 MHz is enough for the network, then doubling this bandwidth channel size would be more than sufficient capacity for the network to handle all of the data.

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The answer is False.

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Determine if x(t) is periodic and determine the fundamental period.
Studentka2010 [4]

Answer:

hdiihgguilmjj jduhuiuedoibb

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The size of an array (how many elements it contains), which is accessed by .Lenth() returns (Choose the best answer)
Wewaii [24]

Answer:that creates the array, puts some values in it, and displays the values. ... assign a value to each array element and print for (int i = 0; i < anArray.length; i++) ... Array; Array Initializers; Accessing an Array Element; Getting the Size of an Array ... not create an array and does not allocate any memory to contain array elements.

Explanation:

5 0
3 years ago
Write at leaat 20 shortcuts on the Microsoft word.​
Flauer [41]

Answer:

Open a document: Ctrl + O.

Create a new document: Ctrl + N.

Save the current document: Ctrl + S.

Open the Save As window: F12.

Close the current document: Ctrl + W.

Split the window: Alt + Ctrl + S.

Copy: Ctrl+C

Paste: Ctrl+V

Cut the current selection: Ctrl + X

Copy the current selection: Ctrl + C

Paste the contents of the clipboard: Ctrl + V

Bold: Ctrl + B

Italics: Ctrl + I

Underline: Ctrl + U

Underline words only: Ctrl + Shift + W

Center: Ctrl + E

Make the font smaller: Ctrl + [

Make the font bigger: Ctrl + ]

Change text to uppercase: Ctrl + Shift + A

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Insert a page break: Ctrl + Enter

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Explanation:

3 0
2 years ago
Input an int between 0 and 100 and print the numbers between it and 100, including the number itself and the number 100. If the
Murrr4er [49]

import java.util.Scanner;

public class JavaApplication42 {

   public static void main(String[] args) {

       Scanner scan = new Scanner(System.in);

       int count = 0;

       System.out.println("Enter an integer between 0 and 100");

       int num = scan.nextInt();

       if (num <= 0 || num >= 100){

           System.out.println("error");

       }

       else{

           while(num <= 100){

               if (count == 20){

                   System.out.println("");

                   count = 0;

               }

               else{

                   System.out.print(num+" ");

                   count++;

                   num++;

               }

           }

       }

   }

   

}

I hope this helps!

6 0
3 years ago
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