2 years ago

Help What is the point-slope form of the equation of the line with a slope of 5/3 that goes through point (0,3)?

Mathematics

1 answer:

AnnZ [28]2 years ago

3 0

Y - 3 = 5/3 (x - 0)
this is point slope

y - 3 = 5/3x
y = 5/3x + 3

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Susan divides the fraction LaTeX: \frac{5}{8}5 8by LaTeX: \frac{1}{16}1 16. Her friend Robyn divides LaTeX: \frac{5}{8}5 8by LaT

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Given:

Susan divides the fraction $\dfrac{5}{8}$ by $\dfrac{1}{16}$ .

Her friend Robyn divides $\dfrac{5}{8}$ by $\dfrac{1}{32}$ .

To find:

The quotient of Susan and Robyn.

Solution:

Susan divides the fraction $\dfrac{5}{8}$ by $\dfrac{1}{16}$ .

$\dfrac{\dfrac{5}{8}}{\dfrac{1}{16}}=\dfrac{5}{8}\times \dfrac{16}{1}$

$\dfrac{\dfrac{5}{8}}{\dfrac{1}{16}}=\dfrac{80}{8}$

$\dfrac{\dfrac{5}{8}}{\dfrac{1}{16}}=10$

So, Susan's quotient is 10.

Her friend Robyn divides $\dfrac{5}{8}$ by $\dfrac{1}{32}$ .

$\dfrac{\dfrac{5}{8}}{\dfrac{1}{32}}=\dfrac{5}{8}\times \dfrac{32}{1}$

$\dfrac{\dfrac{5}{8}}{\dfrac{1}{32}}=5\times 4$

$\dfrac{\dfrac{5}{8}}{\dfrac{1}{32}}=20$

So, Robyn's quotient is 20.

Since 20>10, therefore, Robyn will get greater quotient.

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