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miss Akunina [59]
3 years ago
6

What is the sum of the first 5 terms of this geometric series? Use . -4 + 12 + (-36) + ⋯

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
7 0

Answer:

The sum of the first 5 terms is -244

Step-by-step explanation:

To calculate the sum of the geometric series, we need the first term, the common ratio and the number of terms we would like to sum.

The first term here is -4

The common ratio is T2/T1 or T3/T2 = 12/-4 = -3

number of terms n = 5

The formula to use is;

Sn = a(1-r^n)/(1-r)

Plugging these values, we have;

Sn = -4(1-(-3)^5)/(1-(-3))

Sn = -4(1+243)/4 = -1(244) = -244

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Answer:

$21.58

Step-by-step explanation:

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$10.36 × 5.8 = $60.088

$6.64 × 5.8 = 33.512

I did this and that’s the correct answer. I hope it helps…

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Answer:

a) P(X>3.5)=P(\frac{X-\mu}{\sigma}>\frac{3.5-\mu}{\sigma})=P(Z>\frac{3.5-5}{1.2})=P(z>-1.25)

And we can find this probability using the complement rule:

P(z>-1.25)=1-P(z

b) P(X

And we can find this probability uing the normal standard table:

P(z

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And we can find this probability with this difference:

P(-1.25

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-1.25

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(5,1.2)  

Where \mu=5 and \sigma=1.2

We are interested on this probability

P(X>3.5)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>3.5)=P(\frac{X-\mu}{\sigma}>\frac{3.5-\mu}{\sigma})=P(Z>\frac{3.5-5}{1.2})=P(z>-1.25)

And we can find this probability using the complement rule:

P(z>-1.25)=1-P(z

Part b

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability uing the normal standard table:

P(z

Part c

P(3.5

And we can find this probability with this difference:

P(-1.25

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-1.25

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Step-by-step explanation:

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