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3 years ago

9

the outdoor temperature was 8 degrees at midnight. The temperature declined 5 degree during each of the next 3 hours What was th

e temperature at 3am???? I NEED HELP

1 answer:

kompoz [17]3 years ago

4 0

I would say it was 3 degrees at 3am

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I WILL GIVE BRAINLIEST

PolarNik [594]

Answer: It should be 1/2, 50% or 0.5

Step-by-step explanation: There are only two different things you can get when flipping the coin, so it would be 1/2

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3 years ago

A guy wire runs from the top of a cell tower to a metal stake in the ground. Marques places a 11-foot tall pole to support the g

astra-53 [7]

The Pythagorean theorem computed shows that the length of the guy wire, to the nearest foot, is 207 ft.

<h3>How to solve the length?</h3>

Here, we have two similar right triangles, ΔABE and ΔCDE.

CD = 11 ft

DE = 2 ft

BD = 35 ft

First, find AB:

AB/11 = (35 + 2)/2

AB/11 = 37/2

Cross multiply

AB = (37 × 11)/2

AB = 203.5 ft

Then, apply Pythagorean Theorem to find AE:

AE = √(AB² + BE²)

AE = √(203.5² + 37²)

AE = 207 ft

Therefore, the length of the guy wire is 207 ft.

Learn more about Pythagorean theorem on:

brainly.com/question/654982

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2 years ago

You are saving money to buy a used car. You deposit $2,500 in an account that earns interest compounded annually. The expression

seraphim [82]

Answer:

$r= [(\frac{A}{2500}) ^\frac{1}{2} -1]$

Step-by-step explanation:

Given data

Principal = $2500

time t= 2 years

Required

the rate r

Given the expression for the balance 2500(1+r)^2

Hence

$A= 2500(1+r)^2$

we can make r subject of formula

$r= [(\frac{A}{P}) ^\frac{1}{t} -1]$

$r= [(\frac{A}{2500}) ^\frac{1}{2} -1]$

Hence, for any value of A, we can find the rate using the expression above

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3 years ago

PLEASE HELP!! <br> I HAVE A DEADLINE!!!!!!!!!!!

butalik [34]

C! All angles are the same

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3 years ago

Read 2 more answers

Those are the math questions I need the answers of

Elena L [17]

Answer:

1)

$12\sqrt{18}-3\sqrt{50}+\sqrt{32}$

$12\sqrt{9}\sqrt{2}-3\sqrt{25} \sqrt{2} +\sqrt{16} \sqrt{2}$

$12\times3\sqrt{2} -3\times5\sqrt{2}+4\sqrt{2}$

$36\sqrt{2}-15\sqrt{2}+4\sqrt{2}$

$25\sqrt{2}$

2)

$\frac{1}{5+2\sqrt{6}}$

Multiply $5-2\sqrt{6}$ :

$\frac{1\times \left(5-2\sqrt{6}\right)}{\left(5+2\sqrt{6}\right)\left(5-2\sqrt{6}\right)}$

Apply Difference of Squares formula: $(a+b)(a-b)=a^2-b^2$

$\frac{5-2\sqrt{6}}{5^2-\left(2\sqrt{6}\right)^2}$

$\frac{5-2\sqrt{6}}{25-2^2\left(\sqrt{6}\right)^2}$

$\frac{5-2\sqrt{6}}{25-4\times6}$

$\frac{5-2\sqrt{6}}{1}$

${5-2\sqrt{6}}$

a = 5, b = -2

7 0

4 years ago