3 years ago

Find the zeros of the function (x+3)^2(x-5)^6 and state the multiplicity

1 answer:

3 0

Find the zeros of Function (x)= (x+3)^2(x-5)^6 and state the multiplicity. ... (x--5)^6 = 0=> x--5= 0 => x = 5. Therefore real zero's of the function are --3,5.

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