Answer:
Proved,
P(A∪B)=0.72
Step-by-step explanation:
Sue travels by bus or walks when she visits the shops.
Probability( catch the bus to the shop ), P(A) = 0.4
Probability( catch the bus from the shop ), P(B) = 0.7
Both A and B are independent events.
Therefore,
P(A∩B) = 0.4×0.7
= 0.28
Probability Sue walks one way = 1 - P(A∩B)
= 1 - 0.28
= 0.72
Hence, the probability that Sue walks at one way is 0.72
You need to substitute 9 with every x value in the equation.
So, 3(9)^2-7(9)+11
p(x)= 191
8xy-7xy-3xy-3y²-2y²+8y²+5x²+12x²
then simplify by combining like terms -2xy+3y²+17x²
1)
Parameter = 10+7+3+8+4+8+3+7
Parameter = 50 ft
2)
Area = Area 1 + Area 2
Area = (10x7) + (4x8)
Area = 70 + 32
Area = 102 Sq. Feet
