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3 years ago

Find a solution to the following system of equations. 5x + y = 10 4x + 5y = 8

Mathematics

1 answer:

Alex787 [66]3 years ago

6 0

The solution to this problem is (-2,0). Your welcome, and yes im positive this is the correct answer.

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A student wanted to know the favorite lunch at a large high school with a closed campus. What is the first step in conducting a

Neko [114]

Answer:

Start By How many kids are in your hs

Step-by-step explanation:

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2 years ago

I don’t understand the question

kipiarov [429]

Answer:

Answer is given below with explanations.

Step-by-step explanation:

$- 13 {x}^{2} \: has \: only \: one \: term \: and \: highest \: degree \: is \: 2 \\$

1) Option d) Monomial degree 2

$- 8 {y}^{7} - 3 \: has \: two \: terms \: and \: highest degree \: is \: 7$

2) Option c) Binomial degree 7

HAVE A NICE DAY!

THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION.

6 0

2 years ago

The diameter of bushings turned out by a manufacturing process is a normally distributed random variable with a mean of 4.035 mm

Andrew [12]

A) the z score for 95% is 1.96

Multiply by the deviation:

1.96 x 0.005 = 0.0098

Now add and then subtract that from the mean:

4.035 - 0.0098 = 4.0252

4.035 + 0.0098 = 4.0448

The interval is (4.0252, 4.0448)

B) 4.035 +/- 1.96 x sqrt( 0.005/sqrt(25))

= 4.035 +/-0.00196

Answer: ( 4.033, 4.037)

C) the conclusion is that both 4.020 and 4.055 are out of the range.

4.020 is below the lowest range and 5.055 is higher than highest range.

6 0

3 years ago

A cookie recipe calls for 3⅓ cups of flour to make 4 dozen cookies. You only want to make 24 cookies, though. How much flour s

Svetach [21]

Answer:

2 4/6 = 2 2/3

3 0

2 years ago

Working alone at its constant rate, pump X pumped out ¼ of the water in a tank in 2 hours. Then pumps Y and Z started working an

madam [21]

Answer:

The correct option is B) 12.

Step-by-step explanation:

Consider the provided information.

Working alone at its constant rate, pump X pumped out ¼ of the water in a tank in 2 hours.

As we know: $rate =\dfrac{ work}{time}$ ,

The rate of pump X is $\frac{\frac{1}{4}}{2} = \frac{1}{8}$

$\frac{1}{4}$ of the water is pumped out of the tank, that means only $\frac{3}{4}$ is left to be pumped out.

All 3 pumps pumped out the remaining $\frac{3}{4}$ of the water out in 3 hours.

The combined rate of all three pumps is: $\frac{\frac{3}{4}}{3} = \frac{1}{4}$

Pump Y, working alone at its constant rate, would have taken 18 hours to pump out the rest of the water.

The rate of pump Y = $\frac{\frac{3}{4}}{18} = \frac{1}{24}$

Let z is the time taken by pump Z, then the rate of pump Z is $\frac{1}{z}$ .

Therefore,

$\dfrac{1}{8}+\dfrac{1}{24}+\dfrac{1}{z}=\dfrac{1}{4}$

Multiplying both sides by 24 z.

$3z + z + 24 = 6z\\24 = 2z\\12 = z$

Hence, the correct option is B) 12.

5 0

3 years ago