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aliina [53]
3 years ago
13

What is 3x-2y=24 in slope intercept form??

Mathematics
1 answer:
elixir [45]3 years ago
4 0

Answer:  3x-2y=24 in slope intercept form is y=\frac{2}{3}x -12

The graph of the equation is in the attachment

Step-by-step explanation: Slope intercept form is y = mx + b

m is the slope b is the y-intercept  x is the "input" in the equation y is the "output" or the y-value in the graph for a given x-value.

You need to rearrange the standard form to slope-intercept to isolate y on the left side of the equation.

3x - 2y = 24 Standard form. Subtract 3x from both sides.

-2y = -3x + 24   divide both sides by -2

-2y/-2 = -3x/-2 + 24/-2 . Simplify.

y = 3x/2 - 12 .

To clarify the slope as a fraction

y=\frac{2}{3}x -12

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Simplify the product -3x(x^2+3x-1)
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Answer:

Hii, okay so the answer is, -3x^3-9x^2-1

Hope this helps!

Step-by-step explanation:

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2 years ago
Use the graph of f to estimate the local maximum and local minimum. (5 points)
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The prism below is made of cubes which measure 1/3 of an inch on one side what is the volume
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Answer:

Volume of rectangular prism = 10/9 inch³

Step-by-step explanation:

Given:

Size of each cube = 1/3 inch

Find:

Volume of rectangular prism

Computation:

Length of rectangular prism = 2 x [1/3]

Length of rectangular prism = 2/3 inch

Width of rectangular prism = 3 x [1/3]

Width of rectangular prism = 3/3

Width of rectangular prism = 1 inch

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7 0
2 years ago
Find the number to which the sequence {(3n+1)/(2n-1)} converges and prove that your answer is correct using the epsilon-N defini
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\dfrac{3n+1}{2n-1}=\dfrac{3+\frac1n}{2-\frac1n}\approx\dfrac32

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Now, for the limit as n\to\infty to be equal to \dfrac32 is to say that for any \varepsilon>0, there exists some N such that whenever n>N, it follows that

\left|\dfrac{3n+1}{2n-1}-\dfrac32\right|

From this inequality, we get

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We can then see that choosing N=\left\lceil\dfrac12+\dfrac5{4\varepsilon}\right\rceil will guarantee the condition for the limit to exist. We take the ceiling (least integer larger than the given bound) just so that N\in\mathbb N.
6 0
3 years ago
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