Patrick is collecting data on shoe size. What type of data is this?

Please help math questions <br> put number with answers please

natita [175]

Answer:

See below for answers

Step-by-step explanation:

<u>Problem 1</u>

<u /> $\frac{1}{sin\theta}=2cos\theta\: ; \: 0\leq\theta < 2\pi\\\\1=2sin\theta cos\theta\\\\1=sin2\theta\\\\\frac{\pi}{2}+2\pi n=2\theta\\ \\\frac{\pi}{4}+\pi n=\theta\\ \\\theta=\bigr\{\frac{\pi}{4},\frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\bigr\}$

Therefore, the second option is correct.

<u>Problem 2</u>

<u /> $cos(2x)+1=sin(x)+2\:;\: 0\leq x < 2\pi\\\\1-2sin^2x+1=sin(x)+2\\\\-2sin^2x=sin(x)\\\\0=2sin^2x+sinx\\\\0=sinx(2sinx+1)$

$0=sinx\\\\x=\pi n\\\\x=0,\pi$

$0=2sinx+1\\\\-1=2sinx\\\\-\frac{1}{2}=sinx\\ \\x=\frac{7\pi}{6}+2\pi n,\frac{11\pi}{6}+2\pi n\\\\x=\frac{7\pi}{6},\frac{11\pi}{6}$

Therefore, the solution set is $x=\bigr\{0,\pi,\frac{7\pi}{6},\frac{11\pi}{6}\bigr\}$ , making the second option correct.

<u>Problem 3</u>

<u /> $2cos^2x=-cosx\: ;\: 0^\circ\leq x < 360^\circ\\\\2cos^2x+cosx=0\\\\cosx(2cosx+1)=0$

$cosx=0\\\\x=\frac{\pi}{2}+\pi n\\ \\x=90^\circ+180n^\circ\\\\x=90^\circ,270^\circ$

$2cosx+1=0\\\\2cosx=-1\\\\cosx=-\frac{1}{2}\\\\x=\frac{2\pi}{3}+2\pi n,\frac{4\pi}{3}+2\pi n\\ \\x=120^\circ+360n^\circ,240^\circ+360n^\circ\\\\x=120^\circ,240^\circ$

Therefore, the solution set is $x=\bigr\{90^\circ,120^\circ,240^\circ,270^\circ\bigr\}$ , making the fourth option correct

7 0

3 years ago

Find the x-intercept of 2x+2y=2

Nana76 [90]

Answer:

x-intercept: <u>(1,0)</u>

y-intercept: <u>(0,1)</u>

Step-by-step explanation:

Given: Find the x and y intercepts of 2x + 2y = 2

<h2><u>X-intercept</u></h2>

To solve for a x - intercept we have to substitue 0 in for y and solve for $x$

Lets do it:

2x + 2(0) = 2

2x + 0 = 2

2x = 2

x = 1

Therefore, this means that when y = 0, x = 1 or (1,0)

<h2><u>Y-intercept</u></h2>

To solve for a y - intercept we have to substitue 0 in for x and solve for $y$

Lets do it:

2(0) + 2y = 2

0 + 2y = 2

2y = 2

y = 1

Therefore, this means that when x = 0, y = 1 or (0,1)

3 0

2 years ago

Use the given graph to determine the limit, if it exists. A coordinate graph is shown with a horizontal line crossing the y axis

Lesechka [4]

Answer:

The limit of the function does not exists.

Step-by-step explanation:

From the graph it is noticed that the value of the function is 6 from all values of x which are less than 2. At x=2, the line y=6 has open circle. It means x=2 is not included.

For x<2

$f(x)=6$

The value of the function is -3 from all values of x which are greater than 2. At x=2, the line y=-3 has open circle. It means x=2 is not included.

For x>2

$f(x)=-3$

The value of y is 1 at x=2, because of he close circles on (2,1).

For x=2

$f(x)=1$

Therefore the graph represents a piecewise function, which is defined as

$f(x)=\begin{cases}6& \text{ if } x2 \end{cases}$

The limit of a function exist at a point a if the left hand limit and right hand limit are equal.

$lim_{x\rightarrow a^-}f(x)=lim_{x\rightarrow a^+}f(x)$

The function is broken at x=2, therefore we have to find the left and right hand limit at x=2.

$lim_{x\rightarrow 2^-}f(x)=6$

$lim_{x\rightarrow 2^+}f(x)=-3$

$6\neq-3$

Since the left hand limit and right hand limit are not equal therefore the limit of the function does not exists.

6 0

3 years ago

Read 2 more answers

Please help!! (no links)

attashe74 [19]

Answer:

3/32

Step-by-step explanation:

The first question should be 3/8 as there are 3 "1"s on the spinner. The answer to the last one is "3/32". You take the 3/8 chances to get a one and multiply that by 1/4 to get a "B". Once you multiply you get .09375 which is 3/32 when converted. Please let me know if this is incorrect.

5 0

3 years ago

Twenty-four students took a test. Fourteen students earned an A and 8 students earned a B. A student will be randomly chosen.

Afina-wow [57]

Total students = 24
students earning an A= 14

Probability = 14/24 = 7/12

5 0

3 years ago